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creativ13 [48]
3 years ago
7

Explain how to find the surface area of a net.

Mathematics
2 answers:
Hunter-Best [27]3 years ago
4 0
If the length of one side of the cube 4 units then the area of one its face is 4 × 4 = 16 square units. From the net, we can see that there are six equal faces and so we get the total surface area is 6 × 16 = 96 square units.
maxonik [38]3 years ago
3 0

Answer:

See below

Step-by-step explanation:

<u>Introduction</u><u>:</u><u>-</u>

Nets are a 2-dimensional representation of a 3-dimensional shape.

For example - Imagine a cubical cardboard box , when we open all the sides of the box and lay it on a 2D surface it looks like ( See attachment 1 ) The first 3D figure is a cube and the second figure is of its net .

<u>To </u><u>find </u><u>the </u><u>surface</u><u> area</u><u> of</u><u> </u><u>a </u><u>net </u><u>:</u><u>-</u><u> </u>

Take example of a cube . When we open the sides and lay it on the 2D surface it looks like something as shown in attachment . We can see that it consists of 6 squares of same dimensions . If we take each side of the square to be "a" , then the area of one Square will be ,

  • Area = l × b
  • Area = a × a
  • Area = a²

Therefore area of 6 squares ,

  • Area = 6 × a²
  • Area = 6a²

Similarly , if we take a cuboidal box / rectangular prism , the area of its net will be

  • Area = 2( lb + bh + hl)

where l , b and h are the length, breadth and height of the cuboid .

Hope it helps !

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n the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled ap
Sveta_85 [38]

T = - 7.5 Cos π/12( t - 4 ) + 10.5 varies over the day in a periodic way that can be modeled approximately by a trigonometric function.

<h3>What is trigonometric function?</h3>

The trigonometric functions are actual functions that relate a right-angled triangle's angle to side length ratios. They are extensively employed in all geosciences, including navigation, solid mechanics, celestial mechanics, geodesy, and many more.

<h3>According to the given information :</h3>

Maximum temp. = 18 degree Celsius

Minimum temp. = 3 degree Celsius

The half way between 10 am and 10 pm is 4 am

Temperature data changes throughout the year can be modeled using the sine and cosine functions. The following form of equation can be used to model these data:

T = A cos B(t - C) + D, where A,B,C,D, are constants, T is the  temperature in °C and t is the hour (1–24)

A = amplitude = (Tmax - Tmin)/2

A = (3 - 18)/2 = - 15/2 = -7.5

B = 2π/24 = π/12

C = units translated to the right

C = 4

D = ymin + amplitude = units translated up

D = 7.5 + 3 = 10.5

The formula of the trigonometric function that models the temperature T in Johannesburg t hours after midnight we be

T = - 7.5 Cos π/12( t - 4 ) + 10.5

To know more about trigonometric function visit:

brainly.com/question/16389848

#SPJ4

4 0
2 years ago
WILL GIVE BRAINLIEST
IrinaK [193]
Slope: 3
Y intercept: 11 or (0,11)
Equation: y = 3x + 11
4 0
3 years ago
In a certain year, the population of Smallburg was $4{,}000.$ In the following year, the population increased by $15\%.$ What wa
makkiz [27]

Answer:

4,600

Step-by-step explanation:

To solve this problem, we need to multiply add 15% of 4,000 back to 4,000.

First, change 15% into a decimal:

15% -> \frac{15}{100} -> 0.15

Next, multiply 4,000 by 0.15:

x= 4,000(0.15)

x=600

The last step is to add the 600 back to 4,000:

4,000 + 600 = 4,600

The population of Smallburg the following year was 4,600.

5 0
3 years ago
PLSSSS HELPPPP MEEEEE I WILLLL<br> GIVEEEE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!
olga55 [171]

Answer:

what is your question

Step-by-step explanation:

You did not post your question yet

5 0
3 years ago
Read 2 more answers
25 km<br> 7 km<br> 18 km<br> 24 km<br> Find the area!!
Anna35 [415]

Answer:

75600k^4 m^4 Hope that help !

Step-by-step explanation:

1. Take out the constants (25×7×18×24) kkkkmmmm

2. Simplify 25×7=175 (175×18×24)kkkkmmmm

3. Simplify 175×18=3150 (3150×24)kkkkmmmm

4. 3150×24= 75600kkkkmmmm

5. The answer would be 75600k^4 m^4

7 0
3 years ago
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