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2 years ago

What is the inverse of f(x)=2-2x

1 answer:

6 0

In the usual sense, it has no inverse function. Since it is not an injection (f(0)=f(2)=0), an inverse function would have to map 0 both to 0 and 2, and that’s impossible.

However, if you restrict the domain to [1,+oo> (to make it injective), and the codomain to [-1,+oo> (to make it surjective), then it has an inverse function, given by g(y)=1+sqrt(y+1).

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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!

Rzqust [24]

1.) 12x^2-7x-10
2.) 10x^2+31x-14

3 0

2 years ago

How many solutions does the equation 2x-6=6+2x

Alex_Xolod [135]

Answer:

2 solutions

Step-by-step explanation:

Since the equations are not equal, they provide two solutions. Negative numbers provide no solutions. If they are equal to zero, they have one solution.

5 0

3 years ago

Read 2 more answers

Which graph represents the function f(x)= 0.2^x + 3

Dennis_Churaev [7]

The third graph or bottom left graph represents $f(x) = 0.2^{x} + 3.$

Step-by-step explanation:

Step 1:

To determine which of the given graphs represents the equation $f(x) = 0.2^{x} + 3$ , we substitute some values in the place of x.

When $x=0,$ $f(x) = 0.2^{x} + 3, f(0) = 0.2^{0} + 3= 4.$

Anything with an exponent of 0 will equal 1.

So the graphs on the right side cannot be the answers.

Step 2:

Now we substitute another value to determine which graph represents $f(x) = 0.2^{x} + 3.$

When $x=1,$ $f(x) = 0.2^{x} + 3, f(1) = 0.2^{1} + 3= 4.2.$

The value of f(x) when $x=1$ is lesser than the value of f(x) when $x =0.$

So the third graph or bottom left graph represents $f(x) = 0.2^{x} + 3.$

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3 years ago

Jessie estiments the weight of her cat to be 10 pounds the actual weight of the cat is 13.75 pounds fine the percent error

GarryVolchara [31]

Answer:

The percent error would be 27.27%

Step-by-step explanation:

percent error = \frac{measured - actual}{actual} x 100%

3 0

3 years ago

I dont know how to divide a line segment.

melamori03 [73]

From point A, draw a line segment at an angle to the given line, and about the same length. The exact length is not important. Set the compasses on A, and set its width to a bit less than one fifth of the length of the new line. Step the compasses along the line, marking off 5 arcs. Label the last one C. With the compasses' width set to CB, draw an arc from A just below it. With the compasses' width set to AC, draw an arc from B crossing the one drawn in step 4. This intersection is point D. Draw a line from D to B. Using the same compasses' width as used to step along AC, step the compasses from D along DB making 4 new arcs across the line. Draw lines between the corresponding points along AC and DB. Done. The lines divide the given line segment AB in to 5 congruent parts.

6 0

3 years ago