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3 years ago

Distance: Jack and Jill start from the same point and walk in'opposite directions. Jack

Mathematics

1 answer:

777dan777 [17]3 years ago

6 0

Answer:

t = 6 km/hour

And, J would be 4 km per hour

Step-by-step explanation:

Let us assume the speed of Tom be T

And, the Speed of Jim be J

Given that

T - J = 2 km /hr ...........(i)

After 3 hours distance between them = 30 km

As they are walking in the opposite direction

Thus,

Net speed =T + J

L ÷ (T+J) = 3

30 ÷ (T+J) = 3

T +J =10 ..............(2)

After solving these two equations

2T = 12

t = 6 km/hour

And, J would be 4 km per hour

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an algebra teacher drove by a farmyard full of chickens and pigs.the teacher happened to notice that there were a totals of 100

LiRa [457]

I'll be honest, this is a pretty interesting question. I've never seen anything like it before!

We can start off by making equations with the given. If there are 100 heads, that means that the total number of chickens and pigs combined is 100. Thus, we can form our first equation:

p + c = 100
('p' represents number of pigs, and 'c' represents number of chickens)

We also know that there are 270 legs total. Since chickens have 2 and pigs have 4, we can make the following equation:
2c + 4p = 270

I suppose the quickest way to solve for this equation is to use the subtraction method. Put the equations on top of each other:

2c + 4p = 270
c + p = 100
___________
Multiply the bottom equation by -2;

2c + 4p = 270
-2c -2p = 100
____________
"Add" these two equations together:

2c + 4p = 270
-2c -2p = -200
___________
2p = 70

Divide both sides by 2:
p = 35

Ah, finally. Now that we know that there are 35 pigs, input this variable into the first equation to find the number of chickens:

c + 35 = 100
Subtract:
c = 65

There are 35 pigs and 65 chickens
-T.B.

3 0

3 years ago

In a doctor's waiting room, there are 14 seats in a row. Eight people are waiting to be seated. There is someone with a very bad

diamong [38]

Answer: 12,972,960

Step-by-step explanation: There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:

So 5 people and (3) could be considered as 6 entities:

Since the order matters, we have to use permutation:

¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!

2,162,160 x 6 = 12,972,960 ways.

Another way to solve this problem is as follow:

5 + (3) people are considered (for the time being) as 6 entities:

The 1st has a choice among 14 ways

The 2nd has a choice among 13 ways

The 3rd has a choice among 12 ways

The 4th has a choice among 11 ways

The 5th has a choice among 10 ways

The 6th has a choice among 9ways

So far there are 14x13x12x11x10x9 = 2,162,160 ways

But the 3 (that formed one group) could seat among themselves in 3!

or 6 ways:

Total number of permutation = 2,162,160 x 6 = 12,972,960

5 0

3 years ago

Help me fellow idiots (jk)

Ierofanga [76]

Answer:

$\frac{4}{5}$

8 0

3 years ago

Find X when x equals negative 15

Ann [662]

Judging by the question you have provided I came to the conclusion that you have already solved your own problem!

If the goal is to find X when X=-15 then your answer for X should be -15!

If this is not the entire equation please post the entire one!

Hope this helped!
-Blake

7 0

3 years ago

Find the mode of 3, 6, 4, 3, 2, 4, 7, 8, 6, 3, 9

lions [1.4K]

Answer:

3 is the mode because it appears most often.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers