Question

A curve in polar coordinates is given by: r=9+3cosθ. Point P is at θ=21π/18 .?

Answer 1

Answer:

Step-by-step explanation:

Given that a curve in polar coordinates is given by:

r=9+3cosθ

a) At point P, we have

$θ=\frac{21\pi}{18}$

Substitute to get

$r=9+cos \frac{21\pi}{18}\\=9.3932$

b) Cartesian coordinate is

$x= rcos \theta=3.6934\\y =r sin \tjeta =8.6365$

c) At the origin r =0

when r =0

we have

$9+3cos\theta=0\\cos\theta =-3$

Since cos cannot take values as -3 it doe snot pass through origin.