Answer:
y = 3/2x by making use of angle relationships in triangles
Step-by-step explanation:
Here's one way to solve it.
∠ADE is an external angle to ΔBDE. As such, its measure will be the sum of the measures of the remote interior angles, ∠DBE and ∠DEB:
∠ADE = 2x° +y°
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If we call the intersection point of AC and DE point G, then ∠AGE is an exterior angle to ΔADG. As such, its measure is the sum of the remote interior angles:
∠AGE = ∠GAD +∠GDA
3y° = x° +(2x° +y°)
2y = 3x . . . . . . . . . . subtract y°, collect terms, divide by °
y = (3/2)x . . . . . . . . divide by 2
Answer:
This is a complicated problem
Step-by-step explanation:
it's called collatz conjecture and well is just unsolved problems
Answer:
7/12
Step-by-step explanation:
The nth term Tₙ = n(n-4) /n+3.
The 1st term T₁ = 1(1 - 4)/(1 + 3) = -3/4
The 6th term T₆ = 6(6 - 4)/(6 + 3) = 6(2)/9 = 2(2)/3 = 4/3
So, the sum of the 1st and 6th terms is T₁ + T₆ = -3/4 + 4/3
= (-9 + 16)/12
= 7/12
Answer:
D. because all irrational numbers are real numbers.
Step-by-step explanation:
Real numbers include virtually all numbers we can come up with, either negative or positive, rational or irrational, decimals, etc. They are not imaginary numbers.
Irrational numbers include all numbers that cannot be written as a quotient of two integers. They are numbers whose decimals are never terminating. Examples include π, √2 etc.
Irrational are a subset of real numbers.
Therefore, the correct venn diagram that shows this relationship between Set R {real numbers} and Set Q {irrational numbers} is the venn diagram in option D (last option), because, all irrational numbers are real numbers.
