9514 1404 393
Answer:
14,201 years
Step-by-step explanation:
The two compound interest formulas are ...
A = P·e^(rt) . . . . . continuous compounding at rate r for t years
A = P·(1 +r/365)^(365t) . . . . . daily compounding at rate r for t years
We went the amounts to be equal:
1000·e^(0.07t) = 1100·(1+0.07/365)^(365t)
Dividing by 1000(1 +0.07/365)^(365t), we have ...
((e^0.07)/(1+0.07/365)^365)^t = 1.1
The base of the exponential on the left is ...
( e^0.07)/(1+0.07/365)^365 ≈ 1.00000671149321522
Taking logs, we have ...
t×ln(1.00000671149321522) = ln(1.1)
t = ln(1.1)/ln(1.00000671149321522) ≈ 0.09531018/(6.7114704·10^-6)
t ≈ 14,201.09 . . . . . years
It will take about 14,201 years for the investments to be equal.
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<em>Additional comment</em>
The investment value at that time will be about $5.269·10^434. (That's a larger number than <em>anything</em> countable in the known universe, including energy quanta.)
These calculations are beyond the ability of many calculators, so might need to be carefully rewritten if the calculator only keeps 10 significant digits, or only manages exponents less than 100.
This shows that daily compounding is very close in effect to continuous compounding. It would take almost 150 years to make a difference of 0.1% in value.
