The first thing you must do is to calculate the weight of the gravel (w) that the truck holds (7.5 yards³). So, you have:
If the weight of 1 yard³ is 1.48 tons, then the weight of 7.5 yards³ is:
w=7.5x1.48 tons
w=11.1 tons
The problem says that the gravel will be placed in containers that each hold 3.7 tons of gravel,so, If they need 1 cotainer to place 3.7 tons, how many containers they need to place 11.1 tons?
1 container-------3.7 tons of gravel
x-------11.1 tons of gravel
x=(11.1x1)/3.7
x=11.1/3.7
x=3 containers
H<span>ow many containers of this size are needed to hold all the gravel from one truck?
</span>
The answer is: 3 containers.
Answer:
93.4 g/mL x 20. mL = 1868g.
489.7m / 53.061 s = 9.23 m/s
216.3 m/66.4 s = 3.26 m/s.
Step-by-step explanation:
Let's analyze each case.
93.4 g/mL x 20. mL
Hewe we are multiplying g/ml*ml. So we have the answer is (g*ml/ml) = g.
So
93.4 g/mL x 20. mL = 1868g.
489.7m / 53.061 s
We are dividing a measurement in m by a measurement in s. So the answer is in m/s.
So
489.7m / 53.061 s = 9.23 m/s
216.3 m/66.4 s
Same as above.
We are dividing a measurement in m by a measurement in s. So the answer is in m/s.
So
216.3 m/66.4 s = 3.26 m/s.
Step-by-step explanation:
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Answer:
c
Step-by-step explanation:
3 and 3/7 ok hope it helps
