after solving
we get ![\frac{125x^{27}}{8y^{39}}](https://tex.z-dn.net/?f=%5Cfrac%7B125x%5E%7B27%7D%7D%7B8y%5E%7B39%7D%7D)
Step-by-step explanation:
We need to simplify the expression:
![\left(\frac{\left2x^{-7}y^7\right}{5x^2y^{-6}}\right)^{-3}](https://tex.z-dn.net/?f=%5Cleft%28%5Cfrac%7B%5Cleft2x%5E%7B-7%7Dy%5E7%5Cright%7D%7B5x%5E2y%5E%7B-6%7D%7D%5Cright%29%5E%7B-3%7D)
Solving
![=\frac{1}{\left(\frac{\left2x^{-7}y^7\right}{5x^2y^{-6}}\right)^{3}}\\\\=\frac{1}{\left(\frac{\left2y^{7+6}\right}{5x^{2+7}}\right)^{3}}\\=\frac{1}{\left(\frac{\left2y^{13}\right}{5x^{9}}\right)^{3}}\\=\frac{1}{\left(\frac{\left2^3y^{13*3}\right}{5^3x^{9*3}}\right)}\\=\frac{1}{\left(\frac{\left8y^{39}\right}{125x^{27}}\right)}\\We\,\,know\,\,\frac{1}{\frac{b}{a}}=\frac{a}{b}\\Applying the rule:\\=\frac{125x^{27}}{8y^{39}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft2x%5E%7B-7%7Dy%5E7%5Cright%7D%7B5x%5E2y%5E%7B-6%7D%7D%5Cright%29%5E%7B3%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft2y%5E%7B7%2B6%7D%5Cright%7D%7B5x%5E%7B2%2B7%7D%7D%5Cright%29%5E%7B3%7D%7D%5C%5C%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft2y%5E%7B13%7D%5Cright%7D%7B5x%5E%7B9%7D%7D%5Cright%29%5E%7B3%7D%7D%5C%5C%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft2%5E3y%5E%7B13%2A3%7D%5Cright%7D%7B5%5E3x%5E%7B9%2A3%7D%7D%5Cright%29%7D%5C%5C%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft8y%5E%7B39%7D%5Cright%7D%7B125x%5E%7B27%7D%7D%5Cright%29%7D%5C%5CWe%5C%2C%5C%2Cknow%5C%2C%5C%2C%5Cfrac%7B1%7D%7B%5Cfrac%7Bb%7D%7Ba%7D%7D%3D%5Cfrac%7Ba%7D%7Bb%7D%5C%5CApplying%20the%20rule%3A%5C%5C%3D%5Cfrac%7B125x%5E%7B27%7D%7D%7B8y%5E%7B39%7D%7D)
So, after solving
we get ![\frac{125x^{27}}{8y^{39}}](https://tex.z-dn.net/?f=%5Cfrac%7B125x%5E%7B27%7D%7D%7B8y%5E%7B39%7D%7D)
Keywords: Exponents in fractions
Learn more about Exponents in fractions at:
#learnwithBrainly
Answer:
Step-by-step explanation:
Given that,
DE bisects OF, then OB is equal to BF,
So, OB is ½r
Also, DB is equal to BE, so BE = DB = 6 in
So, applying Pythagoras theorem to triangle OBE
OB² + BE² = OE²
(½r)² + 6² = r²
¼r² + 36 = r²
Multiply through by 4
r² + 144 = 4r²
144 = 4r² - r²
144 = 3r²
r² = 144 / 3
r² = 48
r = √48
r = √16×3
r = 4√3 inches
r = 6.93 inches.
So, the radius of the circle is 4√3 inches
Answer:
1 7/10 is your answer.
Step-by-step explanation:
What you have to do is find the GCF.
10 goes into both 5 and 10
<em>8/10 + 9/10 = </em>
<em>17/10 =</em>
1 7/10 is your answer.
Answer:
<em>JONATHAN WILL NEED 14 PAGES.</em>
Explanation:
<em>33 + 67 = 100</em>
<em>100 - 12 = 88</em>
<em>88 ÷ 6 = 14.6666667 </em>
<em>14.6666667 ⇒ </em><u><em>14</em></u>
<em>(Round 14.6666667 down to 14 because Johnathan does not have .6666667 of a page.)</em>
<em></em>
Answer:
y=10 ur weocme fhrjejdjejhdhehwhsjak