We have a system of equations 2x - 4y = 5 and 6x - 3y = 10.
We want to eliminate one variable when we add up the equations.
If we want to eliminate the x variable, we need to multiply the top, bottom or both of the equations with a number that when the equations are added together will eliminate the x variable.
Multiply the top equation by -3.
-3(2x - 4y) = 5 * -3
-6x + 12y = -15
Now when we add the two equations together, the x's will be eliminated.
-6x + 12y = -15
6x + 6y = 10
18y = -5
The x's were eliminated.
Answer:
32
Step-by-step explanation:
54 = 2(C-5)
27 = C-5
32 = C
The answer is going to be y=-1.75 hope this helps!!
Answer:
No, 6 is not a solution to the equation x2-4=5x
Step-by-step explanation:
6(2)-4=5(6)
12-4=30
8=30
The question is basically asking if you replace x with 6, will the equation equal each other on both sides, for example 6=6 or 3.5=3 1/2. In this case the equation gives us 8=30 which means 6 would not be a solution since both sides aren't equal to one another, 30 is bigger than 8.
Answer:
(c) A false negative (concluding the job candidate is not a drug user when he or she indeed is)
Step-by-step explanation:
First, we need to determine if it is possible for type II error to occur or not.
In analysis, type 2 error occurs when the stated null hypothesis is false.
The given null hypothesis here is "a job candidate is not a drug user" which indicates false. This means that option (e) cannot be the solution.
Having established that there is a possibility for an occurrence of type II error.
Next, is to determine the error.
Type II error implies false negative; hence, options (a), (b) and (d) cannot be the solution.
(c) is correct.
