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guapka [62]
3 years ago
9

V=10 e=5 2v divided by e + 4

Mathematics
1 answer:
Vlada [557]3 years ago
3 0
V=10 2(10)= 20 divided by e
E=5 so 20 divided by 5=4
The answer of 2v/e is 4
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what do you do before adding the equation so that one variable will be eliminated when you dd them 2x-4y=5 and 6x-3y=10
Naddika [18.5K]
We have a system of equations 2x - 4y = 5 and 6x - 3y = 10.
We want to eliminate one variable when we add up the equations.

If we want to eliminate the x variable, we need to multiply the top, bottom or both of the equations with a number that when the equations are added together will eliminate the x variable.

Multiply the top equation by -3.

-3(2x - 4y) = 5 * -3
-6x + 12y = -15

Now when we add the two equations together, the x's will be eliminated.

-6x + 12y = -15
6x + 6y = 10
18y = -5

The x's were eliminated.
6 0
4 years ago
What is the solution to the equation below<br> 50+ 4 = 2(C-5)
Ludmilka [50]

Answer:

32

Step-by-step explanation:

54 = 2(C-5)

27 = C-5

32 = C

5 0
3 years ago
0.04(y - 9) +0.16y = 0.12y-0.5<br> y=<br> (Type an integer or a decimal.)
Vladimir [108]
The answer is going to be y=-1.75 hope this helps!!

3 0
3 years ago
i have a problem im struggling with it says. is 6 a solution to the equation x2 - 4=5x explain why or why not?
Eddi Din [679]

Answer:

No, 6 is not a solution to the equation x2-4=5x

Step-by-step explanation:

6(2)-4=5(6)

12-4=30

8=30

The question is basically asking if you replace x with 6, will the equation equal each other on both sides, for example 6=6 or 3.5=3 1/2. In this case the equation gives us 8=30 which means 6 would not be a solution since both sides aren't equal to one another, 30 is bigger than 8.

6 0
4 years ago
An organization is contemplating the implementation of a drug test as part of screening potential employees. The drug test is no
Leviafan [203]

Answer:

(c) A false negative (concluding the job candidate is not a drug user when he or she indeed is)

Step-by-step explanation:

First, we need to determine if it is possible for type II error to occur or not.

In analysis, type 2 error occurs when the stated null hypothesis is false.

The given null hypothesis here is  "a job candidate is not a drug user" which indicates false. This means that option (e) cannot be the solution.

Having established that there is a possibility for an occurrence of type II error.

Next, is to determine the error.

Type II error implies false negative; hence, options (a), (b) and (d) cannot be the solution.

(c) is correct.

5 0
3 years ago
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