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goldfiish [28.3K]
2 years ago
7

An organization is contemplating the implementation of a drug test as part of screening potential employees. The drug test is no

t 100% effective, i.e., it occasionally classifies drug users as nonusers and vice-versa. Assume that the null hypothesis for the test is that a job candidate is not a drug user. Which of the following would be a Type II error?
a. A false positive (concluding the job candidate is a drug user when he or she is not)
b. A true positive (concluding the job candidate is a drug user when he or she indeed is)
c. A false negative (concluding the job candidate is not a drug user when he or she indeed is)
d. A true negative (concluding the job candidate is not a drug user when he or she is not)
e. There cannot be a Type Il error in this kind of drug testing.
Mathematics
1 answer:
Leviafan [203]2 years ago
5 0

Answer:

(c) A false negative (concluding the job candidate is not a drug user when he or she indeed is)

Step-by-step explanation:

First, we need to determine if it is possible for type II error to occur or not.

In analysis, type 2 error occurs when the stated null hypothesis is false.

The given null hypothesis here is  "a job candidate is not a drug user" which indicates false. This means that option (e) cannot be the solution.

Having established that there is a possibility for an occurrence of type II error.

Next, is to determine the error.

Type II error implies false negative; hence, options (a), (b) and (d) cannot be the solution.

(c) is correct.

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Answer:

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Step-by-step explanation:

Given

Dividend = 125x^3 - 8

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Required

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See attachment for complete process.

First, divide 125x^3 by 5x

\frac{125x^3}{5x} =25x^2

Write 25x^2 at the top

Multiply 5x - 2 by 25x^2

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Subtract from 125x^3 - 8

i.e.

125x^3 - 8 - (125x^3 - 50x^2) = 50x^2 - 8

Step 2:

Divide 50x^2 by 5x

\frac{50x^2}{5x} = 10x

Write 10x at the top

Multiply 5x - 2 by 10x

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Subtract from 50x^2 - 8

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50x^2 - 8 - (50x^2 - 20x) = 20x - 8

Step 3:

Divide 20x by 5x

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Write 4 at the top

Multiply 5x - 2 by 4

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Subtract from 20x - 8

i.e.

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Hence:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

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See Explanation

Step-by-step explanation:

<em>The question is incomplete because the area of the parallelogram is missing. However, the following will guide you in answering the question</em>

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