Answer: D
Step-by-step explanation:
A quadratic function has a degree of 2 so there will be two roots. The statement says the function does NOT CROSS THE X-AXIS so there are no real roots. That means both roots must be imaginary (complex).
Answer:
A
Step-by-step explanation:
To evaluate f(2), substitute x = 2 into f(x), that is
f(2) = 2(2)² - 5(2) = 2(4) - 10 = 8 - 10 = - 2 → A
First you want to get it into standard form. which would mean you get the x of the side of the y and divide everything by the y's coefficient in this case 3.
3y-x=a
3y=x+a
y=1/3x+a
Now your going to want to turn this into a perpendicular li e which means you flip the coefficient and make it negitive
y=-3x+a
then we fill in the points.
-1=-3(2)+a
Solve
-1=-6+a
-1+6=a
5=a
Now put it in standard form.
y=-3x+5
1.B - - original function is y = sqrt(x). If we make sqrt(x+4), we will move the original function to the left 4. If we make sqrt(x+4)+3, additionally the original function will be moved up 3.
2.D - original function is y = sqrt(x). If we make sqrt(x-7), we will move the original function to the right 7. If we make 5*sqrt(x-7), additionally the original function will be expanded throw the y-axis.
3.E - original function is y = x^5. If we make -x^5 (multiply x^2 by -1), we will reflect the original function over the x-axis. If we make -x^5 - 4 , we additionally will move the original function down 4.
4.C - original function is y = x^2. If we make (x-3)^2, we will move the original function to the right 3. If we make x^2 - 5 , we will move the original function down 5.
5.A - original function is y = x^2. If we multiply x^2 by 1/3, function will be compressed about the y-axis.
