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3 years ago

Can you guys help me simply this

Mathematics

1 answer:

Dovator [93]3 years ago

3 0

Simplify the expression.
Exact Form:
10
3
10
3
Decimal Form:
3.
¯
3
Mixed Number Form:
3
1
3

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Observe the expression below and select the true statement(s). ore than one answer possible.

mars1129 [50]

Here are the true statements:

The 6 in the third term is a coefficient. It is paired with a variable so it is a coefficient.

The y in the third term is a factor because it is being multiplied by (6x + 7).

The 9 is a constant because it is just a number in the second term.

7 0

3 years ago

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

3 years ago

Which numbers represent the measure of the sides of a right triangle?

Dominik [7]

Answer:

2.8, 4.5, 5.3

numbers represent the measure of the sides of a right triangle.

2.8²+4.5²=5.3²

7.84+20.25=28.09

28.09=28.09

8 0

3 years ago

I need help) (only the answer) *links and wrong answers will be reorted*

scZoUnD [109]

Answer:

Volume of cuboid = 300 in³

Surface area of cuboid = 280 in²

Step-by-step explanation:

Given:

Length = 10 in

Width = 5 in

Height = 6 in

Find:

Volume of cuboid

Surface area of cuboid

Computation:

Volume of cuboid = [L][B][H]

Volume of cuboid = [10][5][6]

Volume of cuboid = 300 in³

Surface area of cuboid = 2[lb][bh][hl]

Surface area of cuboid = 2[(10)(5) + (5)(6) + (6)(10)]

Surface area of cuboid = 2[50 + 30 + 60]

Surface area of cuboid = 2[140]

Surface area of cuboid = 280 in²

4 0

2 years ago

Write expression without using exponents.<br><br> X^2

wariber [46]

Answer:

x(x) or x*x

Step-by-step explanation:

To write this in the expanded form you just multiply the base(x) by itself

6 0

3 years ago