The defining characteristic of all geometric sequences is a common ratio which is a constant when dividing any term by the term preceding it.
In this case the common ratio is: -6/9=4/-6=r=-2/3
An infinite series will have a sum when r^2<1, so in this case the sum will converge to an actual value because (-2/3)^(+oo) approaches zero.
The sum of any geometric sequence is:
s(n)=a(1-r^n)/(1-r), since we have a common ratio of -2/3 and we want to calculate an infinite series, ie, n approaches infinity, the sum becomes simply:
s(n)=a/(1-r) (because (1-r^+oo) approaches 1 as n approaches +oo)
So our infinite sum is:
s(+oo)=9/(1--2/3)
s(+oo)=9/(1+2/3)
s(+oo)=9/(5/3)
s(+oo)=27/5
s(+oo)=54/10
s(+oo)=5.4
Answer:
the answer might be D but I can't verifi because I can't see full screen
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>
Hot dogs- 4 packs (9 times 4 = 36)
Buns - 3 packs (12 times 3 = 36)