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3 years ago

PLS SOMEONE HELP ASAP!!

1 answer:

6 0

The blue ribbon would be 19 inches. We know the red ribbon is 12 inches and it’s 7 inches less than the blue one, so you would add 7 to 12 to figure out that the blue ribbon is 19 inches.

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In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

3 years ago

PLEASE HELP!!!!!

leva [86]

Answer:

11.7 units

Step-by-step explanation:

sq root(2--4)^2+(-7-3)^2

sq root(6)^2 + (-10)^2

sq root (36)+(100)

sq root 136

equals 11.66 which rounds up to 11.7

6 0

3 years ago

What is the answer to 9 + 10?

ivann1987 [24]

Answer:

Step-by-step explanation:

its just addition

8 0

3 years ago

Read 2 more answers

Rate this song

Alex17521 [72]

Answer:

100/100

Step-by-step explanation:

3 0

3 years ago

IMPORTANT <br><br>[how do you]Find sin theta if tan theta = 3/4

zvonat [6]

$\bf tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{adjacent}{4}}\impliedby \textit{let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{3^2+4^2}\implies c=5
\\\\\\
sin(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{hypotenuse}{5}}$

bear in mind that, though the square has two valid roots, one negative and one positive, the hypotenuse is just a radius distance, and therefore is never negative.

5 0

4 years ago