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Burka [1]
3 years ago
13

Find the common difference for the given sequence 1.2, 1.85, 2.5, 3.15, ...

Mathematics
2 answers:
Kay [80]3 years ago
7 0

Answer:

c)0.65

Step-by-step explanation:

k0ka [10]3 years ago
5 0

Answer:

0.65

Step-by-step explanation:

1.2 + 0.65 = 1.85

1.85 + 0.65 = 2.5

2.5 + 0.65 = 3.15

And so on...

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Can you please explain how to solve this?
BlackZzzverrR [31]

Answer:

18

Step-by-step explanation:

hello,

as this is a parallelogram we can write that BE = DE so

15x + 4 = 9x + 6

<=> 15x - 9x + 4 = 6

<=> 6x = 6 - 4 = 2

<=> x = 2/6 = 1/3

so BE = DE = 15/3+4=5+4=9

so BD = BE + DE = 9 + 9 = 18

the correct answer is 18

hope this helps

7 0
3 years ago
Which number should go in the ?<br> 5 + 3 = 3 + 0<br> 5<br> 3<br> 8
soldi70 [24.7K]

Answer:

the answer is 5

Step-by-step explanation:

because 5+3 is 8 and 3+0 is 3 so you need 5 so it can be equal.

hoped i helped

5 0
3 years ago
Read 2 more answers
If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

8 0
1 year ago
Help please quickly
Irina18 [472]

Answer:

:::::::::::::::::::

D

3 0
2 years ago
Yo fab bbbibvuv gffcfsrth frxrctvybuni<br> hgde
goldenfox [79]

Answer:NIce

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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