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Anton [14]
3 years ago
12

A flying cannonball’s height is described by formula y=−16t^2+300t. Find the highest point of its trajectory. In how many second

s after the shot will cannonball be at the highest point?
Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0
<span>Highest point = 1406.25 Number of seconds = 9.375 We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375 So let's calculate the height at t = 9.375. y = -16t^2 + 300t y = -16(9.375)^2 + 300(9.375) y = -16(87.890625) + 300(9.375) y = -1406.25 + 2812.5 y = 1406.25 So the highest point will be 1406.25 after 9.375 seconds. Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.' y = -16t^2 + 300t y = -16(9.375 + e)^2 + 300(9.375 + e) y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e) y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e y = 1406.25 - 16e^2 Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
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3 years ago
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Issac tosses a quarter off of a bridge, creating the shape of a parabola. The parabola can be represented by the equation h=-16t
andreyandreev [35.5K]

Answer:

Step-by-step explanation:

a) the equation representing the parabola is expressed as

h = -16t² - 4t + 20

c) to determine the height after 25 seconds, we would substitute 25 for t into the given equation. It becomes

h = -16(25)² - 4(25) + 20

h = - 10000 - 100 + 20

h = - 10080

d) when the coin lands on the ground, the height would be 0. Therefore,

-16t² - 4t + 20 = 0

Dividing both sides of the equation by 4, it becomes

- 4t² - t + 5 = 0

- 4t² - 5t + 4t + 5 = 0

- t(4t + 5) + 1(4t + 5) = 0

- t + 1 = 0 or 4t + 5 = 0

t = 1 or t = - 5/4

Since t cannot be negative, then t = 1 second

4 0
2 years ago
PLEASE HELP the formula m=12,000+12,000rt/12t gives keri's monthly loan payment where t is the annual interest rate and t is the
tatiyna

Answer:

The answer is below

Step-by-step explanation:

The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.

Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.

m=\frac{12000+12000rt}{12t}\\ but\ m\leq275, \ and \ r=10\%=0.1\\275= \frac{12000+12000(0.1)t}{12t}\\275= \frac{12000}{12t} +\frac{12000(0.1)}{12t}\\275= \frac{1000}{t} + 100\\275-100= \frac{1000}{t} \\175= \frac{1000}{t} \\175t = 1000\\t= \frac{1000}{175}\\ t=5.72\ years

The loan must be at least for 5.72 years for an annual interest rate (r) of 10%

3 0
3 years ago
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mamaluj [8]
6... I think.
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2 years ago
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10xy(4xy^3-7xy+9y^2)
Thepotemich [5.8K]

Answer:

40x^{2} y^{4} -70x^{2} y^{2} +90xy^{3}

Step-by-step explanation:

10xy(4xy^{3} -7xy+9y^2)  

1. 10xy · 4xy^3 = 40x^2y^4

2. 10xy · -7xy = -70x^{2} y^{2}

3. 10xy · 9y^2 = 90xy^3

Final step: add up all of those values together to make an equation!

Answer:  40x^2y^4+ -70x^2y^2+ 90xy^3

Final Answer: 40x^2y^4-70x^2y^2+90xy^3

3 0
3 years ago
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