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Anton [14]
3 years ago
12

A flying cannonball’s height is described by formula y=−16t^2+300t. Find the highest point of its trajectory. In how many second

s after the shot will cannonball be at the highest point?
Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0
<span>Highest point = 1406.25 Number of seconds = 9.375 We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375 So let's calculate the height at t = 9.375. y = -16t^2 + 300t y = -16(9.375)^2 + 300(9.375) y = -16(87.890625) + 300(9.375) y = -1406.25 + 2812.5 y = 1406.25 So the highest point will be 1406.25 after 9.375 seconds. Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.' y = -16t^2 + 300t y = -16(9.375 + e)^2 + 300(9.375 + e) y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e) y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e y = 1406.25 - 16e^2 Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
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y=3x-5 is already in SIF, so we only need to work on the other one.

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Now we have both equations in slope intercept form, so we can start graphing from the y-intercepts and just follow the slopes.

When we do this, we will see that the lines meet at an exactly 90° angle. When a pair of lines does this, it means they are perpendicular.

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3 years ago
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gregori [183]

Answer:

Only A, B and C are the points whose coordinates are equal to 7.

Step-by-step explanation:

Considering the point A

As the location of point A is (0, 7)

The sum of their coordinates is equal to 0 + 7 = 7

Considering the point B

As the location of point B is (2, 5)

The sum of their coordinates is equal to 2 + 5 = 7

Considering the point C

As the location of point C is (6, 1)

The sum of their coordinates is equal to 6 + 1 = 7

Considering the point D

As the location of point D is (4, -3)

The sum of their coordinates is equal to 4 + ( -3 ) = 1

Considering the point E

As the location of point E is (1, -6)

The sum of their coordinates is equal to 1 + ( -6 ) = -5

Considering the point F

As the location of point F is (-2, -4)

The sum of their coordinates is equal to -2 + ( -4 ) = -2 - 4 = -6

Considering the point G

As the location of point F is (-5, -2)

The sum of their coordinates is equal to -5 + ( -2 ) = -5 - 2 = -7

Considering the point H

As the location of point H is (-4, 3)

The sum of their coordinates is equal to -4 + ( 3 ) = -4 + 3 = -1

From the above discussion, only A, B and C are the points whose coordinates are equal to 7.

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