Given that the dealer sells a dozen tires for $240, every 3-tire set costs $60. There are six 2-tire sets in a dozen. Thus, his total revenue should be $360. The total profit is the difference between the total revenue and the total cost. The answer is therefore, the first choice, $120.
Let x = # of original members
Cost per person (originally) = 832/x
Cost per person after 6 more people = 832/(x+6)
Solve 832/x=832/(x+6) +6 (because the cost was reduced by 6
Solve for x.
x = 26 or -32 (but x is number of members, so it can't be negative)
# of original members is 26.
Original cost is 832/26 = $32 per person.
if ∡PQR = 82°, and the ray QS bisects it, it cuts ∡PQR into two equal halves, ∡PQS and ∡RQS, each of which is then 82/2, or 41°.
Ok, so I used the equation Y2 (4) - Y1 (-10) over X2 (2) -X1 (-5).
4 - -10 is 14 since if a minus sign is before a negative number, it becomes positive.
Same goes for 2 - -5. It is 7 since the minus sign is before the negative number. Final answer is 14/7 which can be simpflied to 2/1 since 14 divided by 7 =2. So the distance is 14\7, or 2\1.
