N = nickels and q = quarters
0.05n + 0.25q = 1.90
n = 2q + 3
0.05(2q + 3) + 0.25q = 1.90
0.10q + 0.15 + 0.25q = 1.90
0.10q + 0.25q = 1.90 - 0.15
0.35q = 1.75
q = 1.75/0.35
q = 5 ......there are 5 quarters
n = 2q + 3
n = 2(5) + 3
n = 10 + 3
n = 13 <=== there are 13 nickels
Answer:
x=2(twice)
y=0(twice)
Step-by-step explanation:
This question can be solved using substitution method
So let's solve
y=x+2....(1)
y=x2+5x+6....(2)
Substitute (1) into(2)
X+2=x2+5x+6
Collect like terms
X2+5x-x+6-2=0
X2+4x+4=0
X2+2x+2x+4=0
X(x+2)+2(x+2)=0
(X+2)(x+2)=0
X+2=0
Substrate 2 from both sides
X=-2
X+2=0
X=-2
Let's substitute the value of x into (1)
y=x+2
y=-2+2
Y=0(twice)
Answer:
15.8 sq. in. of paper will be required.
Step-by-step explanation:
The problem is that a drinking cup does not have a cover, so only the lateral surface area counts.
I.e. We need only the first term.
A = pi r l = pi * 1.5 * sqrt(3^2+1.5^2)
= 15.81 sq. in.
Answer:
y = 10
x = 17
Step-by-step explanation:
4y - 3 = 37
4y = 37 + 3
4y = 40
y = 40 / 4
y = 10
3x - 9 = 42
3x = 42 + 9
3x = 51
x = 51 / 3
x = 17
<em>Hope that helps!</em>