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nexus9112 [7]
3 years ago
5

The Skulls, a student social organization, has two different locations under consideration for constructing a new chapter house.

The Skulls' president, a POM student, estimates that due to differing land costs, utility rates, etc., both fixed and variable costs would be different for each of the proposed sites, as follows LocationAnnual FixedVariableAlpha Ave.$5,000 $200per personBeta Blvd.$8,000 $150per person If it is estimated that 30 persons will be living in this new chapter house, which location should the Skulls select
Business
1 answer:
dangina [55]3 years ago
7 0

Answer:

The Skulls

The location that Skulls should select is:

Alpha Avenue.

Explanation:

a) Data and Calculations:

Estimated number of persons living in this new chapter house = 30

                    Fixed       Variable                   Total Cost

Alpha Ave. $5,000       $200 per person     $11,000

Beta Blvd.  $8,000        $150 per person    $12,500

b) The location that Skulls should select must minimize the total cost.  The location which meets this criterion is Alpha Avenue, with a total cost of $11,000.  This is purely because of the number of persons living in the chapter house.  Assuming that this number would increase, then it may be considered economically better to choose the Beta Boulevard instead of the Alpha Avenue.

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On her way to a concert, Hermione stopped at a restaurant for dinner. In her purse, she had 12 bills worth a total of $40. She h
katovenus [111]

The correct statement will be that the maximum number of $5 bills that can be in Hermione's purse will be 7. So, the correct option that matches the statement is D.

The number of bills of $5 are seven, as Hermione also has at least one bill of $1.

<h3>Calculation of bills. </h3>

  • Considering Hermione has at least one bill of $1, then the computation of total bills out $40 can be shown as below,

  • 40= 1+x

  • where <em>x </em>is the number of $5 bills

  • So we know that the maximum number of bills of $5 that can be kept by Hermione is 7 as $35 is the nearest number possible and seven bills of $5 will constitute $35.

Hence, it can be concluded that option D is correct that there are seven bills of $5 in the purse of Hermione and hence there will be five bills of $1  in her purse.

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2 years ago
Hillside issues $2900000 of 9% 15-year bonds dated January 1, 2017, that pay interest semiannually on June 30 and December 31. T
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Answer:

Dr. Cash                                                 $3,549,590

Cr. Premium on Account Receivable  $649,590

Cr. Bond Payable Account                   $2,900,000

Explanation:

The difference between the face value of the bond and the sale value of the bond is known as premium or the discount on the bond. If the face value is higher from the sale value the bond is issued on the discount and if the sale value of the bond is higher than the face value the bond is issued on the premium.

Premium on the Bond =  Face value - Sale value = $3,549,590 - $2,900,000  = $649,590

The Premium will be amortized during the life of the bond  to maturity and deducted from the interest expense.

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A customer is interested in purchasing new furniture for their living room. Using a mobile phone, the customer opens a special a
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8 0
2 years ago
Let $S$ be the set of complex numbers of the form $a + bi,$ where $a$ and $b$ are integers. We say that $z \in S$ is a unit if t
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Answer:

Number of units possible in S are 4.

Explanation:

Given <em>S</em> is a set of complex number of the form a+bi where <em>a</em> and <em>b</em> are integers.

z\in S is a unit if w\in z exists such that zw=1.

To find:

Number of units possible = ?

Solution:

Given that:

zw = 1

Taking modulus both sides:

|zw| = |1|

Using the property that modulus of product of two complex numbers is equal to their individual modulus multiplied.

i.e.

|z_1z_2|=|z_1|.|z_2|

So,

|zw| = |1|\\\Rightarrow |zw| =|z|.|w| =1\\\Rightarrow |z|=\dfrac{1}{|w|}......... (1)

Let z=a+bi

Then modulus of z is   |z| = \sqrt{a^2+b^2}

Given that a and b are <em>integers</em>, so the equation (1) can be true only when |z| = |w| =1 (Reciprocal of 1 is 1). Modulus can be equal only when one of the following is satisfied:

(a = 1, b = 0) ,  (a = -1, b = 0), (a = 0, b = 1) OR (a = 0, b = -1)

So, the possible complex numbers can be:

1.\ 1 + 0i = 1\\2.\ -1 + 0i = -1\\3.\ 0+ 1i = i\\4.\ 0 -1i = -i

Hence, number of units possible in S are 4.

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