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Vsevolod [243]
3 years ago
11

KE= 0.5 .m.v2 OR PE= m.g.h Kinetic and Potential Energy Practice Problems. Solve the following problems and show your work! 1. A

car has a mass of 2,000 kg and is traveling at 28 meters per second. What is the car's kinetic energy? I​
Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

784000J or 784KJ

Step-by-step explanation:

Kinetic energy (KE) can be represented with the formula

KE = 1/2(MV²)

where

M = Mass of object (Kg) =2000kg

V = velocity or speed of object in metre per second (m/s or ms^-1) = 28m/s

therefore

KE = 1/2(mv²) becomes

KE = (1/2) X 2000 X 28 X 28

KE = 784000Joules

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Log4 216-log4 8 =log4 x
tekilochka [14]
216/8= 27. X= 27. Subtract you divide
4 0
3 years ago
Law of cosines.Anyone good in Trigonometry?​
marin [14]

Answer:

c=11.8\ units

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

c^2=a^2+b^2-2(a)(b)cos(C)

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

a=3\ units\\b=10\ units

C=120^o

substitute the given values

c^2=3^2+10^2-2(3)(10)cos(120^o)

c^2=109-(60)cos(120^o)

c^2=109-(60)(-0.5))

c^2=109+30

c^2=139

c=11.8\ units

3 0
2 years ago
Mari has 3 friends who are available to go with her to the movies, but she only has 2 extra tickets. How many different choices
aliina [53]

Answer:

3 different choices

Step-by-step explanation:

This problem is a combination problem: She has 3 friends, and we want to know how many groups of 2 friends there are. We can solve this using the combination of 3 choose 2:

C(3,2) = 3!(1! * 2!) = 3*2/2 = 3 possibilities

If we call her three friends A, B and C, the groups that can be formed are:

A and B

A and C

B and C

6 0
3 years ago
25. Michael is studying population changes in two
g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

<u>Average Rate of Change</u>

<em><u>Bird A</u></em>:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{9.1 - 8.3}{18 - 0}

Average = 0.045

<em><u>Bird B</u></em>: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{68.7 - 0}{18 - 0}

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

4 0
2 years ago
Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added toge
Anna11 [10]

Answer:

The correct answer is A.

Step-by-step explanation:

1/5*-10/1=-10/5= -2

2/3*3/1=6/3=      2

----------------------------

                          0.

3 0
3 years ago
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