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disa [49]
3 years ago
8

the list shows how much yarn mary has= 1/3 red yarn, 2/9 white yarn, 2/6 blue yarn what is the total amount of yarn mary has?

Mathematics
1 answer:
zlopas [31]3 years ago
4 0

The total amount of yarn Mary has is \frac{8}{9}.

Step-by-step explanation:

Mary has;

Red yarn = \frac{1}{3}

White yarn = \frac{2}{9}

Blue yarn = \frac{2}{6}

Total yarn = Red + White + Blue

Total yarn = \frac{1}{3}+\frac{2}{9}+\frac{2}{6}\\

Taking LCM = 18

Total yarn = \frac{6+4+6}{18}

Total yarn = \frac{16}{18}=\frac{8}{9}

The total amount of yarn Mary has is \frac{8}{9}.

Keywords: fraction, addition

Learn more about fractions at:

  • brainly.com/question/2150928
  • brainly.com/question/2154850

#LearnwithBrainly

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Can you help me please ​
Olenka [21]

Answer:

log_372 = 3.8928

Step-by-step explanation:

Given

log_38 = 1.8928

Required

Evaluate log_372

We have:

log_372 = log_3(8 *9)

Apply law of logarithm

log_372 = log_38 +log_39

Express 9 as 3^2

log_372 = log_38 +log_33^2

Evaluate the exponents

log_372 = log_38 +2log_33

log_33 = 1.

So:

log_372 = log_38 + 2 * 1

log_372 = log_38 + 2

Substitute log_38 = 1.8928

log_372 = 1.8928 + 2

log_372 = 3.8928

5 0
2 years ago
If BY = 6, YC = 10, AX = 18, then XC = <br> a: 10.8 <br> b:5 <br> c:30 <br> d:48
vampirchik [111]
To answer this item, we assume that the topic is in similar polygons such that the ratio of the corresponding sides should be equal. In this item,

    BY/YC = AX/XC

Substituting the known values,

    6/10 = 18/XC

The value of XC from the equation is 30. The answer is letter C. 
3 0
3 years ago
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Decide if each question is statistical or nonstatistical.
lidiya [134]

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Solve for x. x -5 x 7 ÷(8 - 9)<br> help lease
Colt1911 [192]
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3 years ago
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The dot plots below show the scores for a group of students for two rounds of a quiz: Two dot plots are shown one below the othe
miskamm [114]

Answer:

The inference that can be made using the dot plot is:

    The range of round 1 is greater than the round 2 range.

Step-by-step explanation:

<u>Round 1:</u>

Score                Frequency

  1                          0

  2                          2

  3                          3

  4                          2  

  5                          1

Hence, the minimum score of Round 1 is: 2

maximum score is: 5

Hence, Range=Maximum value-Minimum score

                      =5-2

                       =3

Similarly, <u>Round-2</u>

Score                Frequency

  1                          0

  2                         0

  3                          0

  4                          4  

  5                          4

Hence, the minimum score of Round 1 is: 4

maximum score is: 5

Hence, Range=Maximum value-Minimum score

                      =5-4

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The scores of round 2 are higher than round-1.

Since round 2 have a higher frequency for higher scores as compared to round-1.

Hence, Range of round 1 is greater than the range of Round-2.

 

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3 years ago
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