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AnnyKZ [126]
3 years ago
8

Uhh please help 4 spring break hamwork math btwww

Mathematics
2 answers:
elena-s [515]3 years ago
8 0

Answer:

60x + 42y

Step-by-step explanation:

kvasek [131]3 years ago
5 0

Answer:

60x + 42y

Step-by-step explanation:

6(10x + 7y)

Use distribute property and multiply 6 to everything inside the parenthesis:

6 x 10x = 60x

6 x 7y = 42y

SO, 60x + 42y is the correct answer

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5/6 + 3j = -2/3 I need to find the value of j
weeeeeb [17]

5/6 + 3j = -2/3

Multiply all terms by 3.

5/2 = 3j - 2

Multiply all terms by 2.

5 = 6j - 4

Add 4 to both sides.

9 = 6j

Divide both sides by 6.

j = 1.5

8 0
3 years ago
Which of the following fractions is closer to 0 than to 1
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3 years ago
Read 2 more answers
Suppose cos(x)= -1/3, where π/2 ≤ x ≤ π. What is the value of tan(2x). EDGE
AVprozaik [17]

Answer:

D

Step-by-step explanation:

We are given that:

\displaystyle \cos x = -\frac{1}{3}\text{ where } \pi /2 \leq x \leq \pi

And we want to find the value of tan(2<em>x</em>).

Note that since <em>x</em> is between π/2 and π, it is in QII.

In QII, cosine and tangent are negative and only sine is positive.

We can rewrite our expression as:

\displaystyle \tan(2x)=\frac{\sin(2x)}{\cos(2x)}

Using double angle identities:

\displaystyle  \tan(2x)=\frac{2\sin x\cos x}{\cos^2 x-\sin^2 x}

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

\displaystyle o=\sqrt{3^2-1^2}=\sqrt{8}=2\sqrt{2}

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.

From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence:

<h2>\displaystyle  \tan(2x)=\frac{2(2\sqrt{2}/3)(-1/3)}{(-1/3)^2-(2\sqrt{2}/3)^2}</h2>

Simplify:

\displaystyle  \tan(2x)=\frac{-4\sqrt{2}/9}{(1/9)-(8/9)}

Evaluate:

\displaystyle  \tan(2x)=\frac{-4\sqrt{2}/9}{-7/9} = \frac{4\sqrt{2}}{7}

The final answer is positive, so we can eliminate A and B.

We can simplify D to:

\displaystyle \frac{2\sqrt{8}}{7}=\frac{2(2\sqrt{2}}{7}=\frac{4\sqrt{2}}{7}

So, our answer is D.

7 0
3 years ago
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marin [14]
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