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2 years ago

Write the equation of the line given a slope of 0 through the point (5, -7)

Mathematics

1 answer:

wlad13 [49]2 years ago

6 0

Answer:

y=-7

Step-by-step explanation:

y-y1=m(x-x1)

y-(-7)=0(x-5)

y+7=0

y=0-7=-7

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Hannah is at the supermarket to buy carrots and potatoes. If she buys 2 pounds of carrots and 3 pounds of potatoes, it will cost

zhenek [66]

Answer:

Carrots cost $ 1.75 a pound which is more than potatoes cost.

Step-by-step explanation:

Let,

Carrots cost $ x per pound and potatoes cost $ y per pound.

Buying 2 pounds of carrots and 3 pounds of potatoes will cost her

$ $(2\times x + 3\times y)$

and

Buying 4 pounds of carrots and 4 pounds of potatoes will cost her

$ $(4\times x + 4\times y)$

According to the question,

$(2\times x + 3\times y) = 8$ -----(1)

$(4\times x + 4\times y) = 13$ -----(2)

multiplying (1) by 2 we get,

$(4\times x + 6\times y) = 16$ -----(3)

Deducting (2) from (3) we get,

$2\times y = 3$

⇒ $y = \frac{3}{2} = 1.5$ ------------------(4)

Putting value of y in (1) we get,

$(2\times x = 8 - 3\times 1.5) = 3.5$

⇒ $x =\frac{3.5}{2} = 1.75$ ------------(5)

8 0

3 years ago

Bianca filled 2 same-sized jars with flavored popcorn as a gift. She wants to glue a piece of ribbon around the edge of each lid

dybincka [34]

I think it is 177.4728

but im not sure let me check

7 0

3 years ago

Read 2 more answers

What should be done to solve the equation?

stellarik [79]

Answer:

add 17 to both sides

Step-by-step explanation:

as it cancels itself

mark brainliest

5 0

3 years ago

Use each model to predict the life expectancy of residents of a country for which the average annual income is $80,000

Mandarinka [93]

The life expectancies of residents of a country for which the average annual income is $80,000 for the three models are 12309.9352, 172.2436 and 4828.1393

The life expectancies of the models are given as:

$y =69.9352 + 0.1530\times (income)$ --- model 1

$y =4.2436 + 0.0021\times (income)$ --- model 2

$y =4.1393 + 0.0603\times (income)$ --- model 3

Given that the average annual income is $80,000;

We simply substitute 80000 for income in the equations of the three models.

So, we have:

Model 1

$y =69.9352 + 0.1530\times (income)$

$y =69.9352 + 0.1530\times 80000$

$y =12309.9352$

Model 2

$y =4.2436 + 0.0021\times (income)$

$y =4.2436 + 0.0021\times 80000$

$y =172.2436$

Model 3

$y =4.1393 + 0.0603\times (income)$

$y =4.1393 + 0.0603\times 80000$

$y =4828.1393$

Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393