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lina2011 [118]
4 years ago
9

How would you compare 3.6 and the root of 12?

Mathematics
1 answer:
Luden [163]4 years ago
8 0

\sqrt{12}

can be simplify as

\sqrt{4}  \times  \sqrt{3}

= 2 \sqrt{3}

= 3.46

now comparing 3.6 to 3.46

we can say that

3.6 > 3.46 (√12)

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2 years ago
Read 2 more answers
Solve without using a calculator:<br><br> sin²20° + sec²20°
PolarNik [594]

Step-by-step explanation:

sin

2

(

20

°

)

+

sec

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(

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Simplify each term.

Tap for fewer steps...

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(

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+

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1

cos

(

20

°

)

)

2

Apply the product rule to

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20

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sin

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(

20

°

)

+

1

2

cos

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(

20

°

)

One to any power is one.

sin

2

(

20

°

)

+

1

cos

2

(

20

°

)

Simplify each term.

Tap for fewer steps...

Rewrite

1

as

1

2

.

sin

2

(

20

°

)

+

1

2

cos

2

(

20

°

)

Rewrite

1

2

cos

2

(

20

°

)

as

(

1

cos

(

20

°

)

)

2

.

sin

2

(

20

°

)

+

(

1

cos

(

20

°

)

)

2

Convert from

1

cos

(

20

°

)

to

sec

(

20

°

)

.

sin

2

(

20

°

)

+

sec

2

(

20

°

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The result can be shown in multiple forms.

Exact Form:

sin

2

(

20

°

)

+

sec

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(

20

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)

Decimal Form:

1.24945210

7 0
3 years ago
A woman wants to build a rectangular garden. She plans to use a side of a shed for one side of the garden. She has 84 yd of fenc
Ivan
Let x denote the length of the side of the garden which is covered fenced by a shed, and \frac{A}{x} be the width of the garden.

The perimeter of a rectangle is given by 2(length + width)
i.e. 2x + \frac{A}{x} = 84
which gives:
A = 84x - 2x^2

For the area to be maximum, the differentiation of A with respect to x must be equal to 0.
i.e. \frac{dA}{dx} =84-4x=0 \\ 4x=84 \\ x=21

Therefore, the maximum area of the garden enclosed is given by
84(21)-2(21)^2=1764-2(441)=1764-882=882 \, yd^2

3 0
4 years ago
Not sure how to do this, how would I solve it ?
s344n2d4d5 [400]
Attached is how to do it.
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7 0
3 years ago
What equations can you use to get the number 12
Vsevolod [243]
6x6, 4x3, 8+4x 9+3, 24/2
8 0
3 years ago
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