The price of a new car is $20,000. If it has a depreciation rate of 18% per year, what is its value in 3 yr?

Mathematics

2 answers:

Artemon [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Depreciation in 1st year= 18%×$20,000=18÷100×$20,000= 0.18×$20,000=$3600

New value=$20,000-$3600=$16,400

Depreciation in 2nd year=18% of $16,400=0.18×16,400=$2,952

New value=$16,400-$2,952=$13,448

Depreciation in 3rd year=18% of $13,448=0.18×$13,448=$2,420.64

New value=$13,448-$2,420.64=$11,027

.36

KonstantinChe [14]3 years ago

5 0

Answer: After 3 years the value of the new car would be $11,027.36

You might be interested in

A nursery has $50,000 of inventory in dogwood trees and red maple trees. The profit on a dogwood tree is 27% and the profit on a

nasty-shy [4]

Answer:

Sorry do not have your answer

Step-by-step explanation:

5 0

2 years ago

Simplify each expression. Write your answers in exponential notation.

GenaCL600 [577]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad
a^n\implies \cfrac{1}{a^{-n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{36b^3}{9a^5} \right)^3\implies \left( \cfrac{4b^3}{a^5} \right)^3\implies \stackrel{\textit{distributing the exponent}}{\left(\cfrac{4^3b^{3\cdot 3}}{a^{5\cdot 3}}\right)}\implies \cfrac{64b^9}{a^{15}}$

3 0

3 years ago

A rectangular prism has a length of 5 cm, a width of

kobusy [5.1K]

A rectangular prism has a length of 5 cm, a width of
2.
cm, and a height of 1 cm
cm.
Which expressions can be used to find the volume of the prism?
Select each correct answer.
5 • 2 1/2
12 1/2 • 1 1/2
1 1/2 (5 + 2 1/2)
1/2 (12 1/2 • 1 1/2)

8 0

3 years ago

Read 2 more answers

What is j(3) equal to?<br> j:t = 4t^2<br> I(3)=?

VARVARA [1.3K]

4*3^2 = 36. Is that what you meant?

3 0

3 years ago

5, if r = 3?<br> what is the answer

Papessa [141]

Answer:

Step-by-step explanation: