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blagie [28]
3 years ago
9

The price of a new car is $20,000. If it has a depreciation rate of 18% per year, what is its value in 3 yr?

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Depreciation in 1st year= 18%×$20,000=18÷100×$20,000= 0.18×$20,000=$3600

New value=$20,000-$3600=$16,400

Depreciation in 2nd year=18% of $16,400=0.18×16,400=$2,952

New value=$16,400-$2,952=$13,448

Depreciation in 3rd year=18% of $13,448=0.18×$13,448=$2,420.64

New value=$13,448-$2,420.64=$11,027

.36

KonstantinChe [14]3 years ago
5 0

Answer: After 3 years the value of the new car would be $11,027.36

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An expression is defined as a set of numbers, variables, and mathematical operations. The given expression when simplified will be equal to 14¹⁰. The correct option is A.

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The given expression can be simplified as shown below.

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Using the exponential property 1/aˣ = a⁻ˣ, we can write,

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Using the exponential property aˣ × aᵇ = a⁽ˣ⁺ᵇ⁾, we can write,

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