Answer:
Step-by-step explanation:
Depreciation in 1st year= 18%×$20,000=18÷100×$20,000= 0.18×$20,000=$3600
New value=$20,000-$3600=$16,400
Depreciation in 2nd year=18% of $16,400=0.18×16,400=$2,952
New value=$16,400-$2,952=$13,448
Depreciation in 3rd year=18% of $13,448=0.18×$13,448=$2,420.64
New value=$13,448-$2,420.64=$11,027
.36
Answer: After 3 years the value of the new car would be $11,027.36
a) 3x⁴-4x³-8x²-35x-10
3x2(x²-3x-1)+5x(x²-3x-1)+10(x²-3x-1)
3x⁴-9x³-3x²+5x³-15x²-5x+10x²-30x-10
3x⁴-9x³+5x³-3x²-15x²+10x²-5x-30x-10
3x⁴-4x³-8x²-35x-10
x = -1/2 and -2
Solve for <em>x</em>: Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Using the quadratic formula: Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
