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3 years ago

Hiram asked his math class, "How many pets do you own?" He graphed the results on the line plot.

Mathematics

2 answers:

Leni [432]3 years ago

7 0

Answer:

B The median is 2.5; the distribution is symmetrical; and there are no gaps or outliers.

Step-by-step explanation

when I find the median it gets to 2, 3 so I get 2.5 no gaps and 0-7 isn't that far

Zanzabum3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

1. You mix the letters S, U, M, M, E, and R in a bag. Without looking, you select one letter. Find the probability of each event

Lena [83]

Sample space ={S, U, M, M, E, R} = 6 outcomes. Event selecting S: P(S) =1/6 = 16.67% Event selecting U: P(U) =1/6 = 16.67% Event selecting M: P(M) =2/6 = 1/3 = 33.34% Event selecting E: P(E) =1/6 = 16.67% Event selecting R: P(R) =1/6 = 16.67%

8 0

3 years ago

Read 2 more answers

A candy company claims that 25% of the candies in its bags are colored green. Steve buys 32 bags of 32 candies, randomly selects

Luden [163]

Answer:

45.88%

Step-by-step explanation:

We have in this case a binomial distribution when p = 0.25, since the probability is 25%

. The formula that we will use in excel is BINOM.DIST, separated by commas we must put the value of x, n, p and also if it is true or false. We know that n equals 32.

In this case we need to know when x = 7, 8 and 9 and add this, and thus we will obtain the probability:

P (X = 7) + P (X = 8) + P (X = 9)

Excel formulas: = BINOM.DIST (7,32,0.25, FALSE) + BINOM.DIST (8,32,0.25, FALSE) + BINOM.DIST (9,32,0.25, FALSE)

P = 0.1546 + 0.1610 + 0.1431

P = 0.4588

Probability that steve agrees with the company's claim 45.88%

4 0

3 years ago

While playing mini golf, you hit the ball off of a wall to attempt at making it in the hole. The ball is located at (5,4) and th

Marta_Voda [28]

It would be 21,12. If thats how u do the math

4 0

3 years ago

Read 2 more answers

Write an equation parallel to 5x-4y=4 that passes through the point (-8,2)

Yuri [45]

Converting to slope intercept form:-

5x - 4y = 4

-4y = -5x + 4

y = 5/4 x - 1 so the slope of the line = 5/4

Finding the line that passes through ( -8, 2) with the same slope:-

y - 2 = 5/4(x - -8) (Point-slope form)

y = 5/4x + 10 + 2

y = 5/4 x + 12 is the answer is slope intercept form

In standard form :-

4y = 5x + 48

5x - 4y = -48 is the answer is standard form

5 0

3 years ago

Read 2 more answers

Let e1= 1 0 and e2= 0 1 , y1= 4 5 , and y2= −2 7 , and let T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps

Furkat [3]

Answer:

The image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is $\left[\begin{array}{c}24&-8\end{array}\right]$

Step-by-step explanation:

We know that $T:$ $IR^{2}$ → $IR^{2}$ is a linear transformation that maps $e_{1}$ into $y_{1}$ ⇒

$T(e_{1})=y_{1}$

And also maps $e_{2}$ into $y_{2}$ ⇒

$T(e_{2})=y_{2}$

We need to find the image of the vector $\left[\begin{array}{c}4&-4\end{array}\right]$

We know that exists a matrix A from $IR^{2x2}$ (because of how T was defined) such that :

$T(x)=Ax$ for all x ∈ $IR^{2}$

We can find the matrix A by applying T to a base of the domain ( $IR^{2}$ ).

Notice that we have that data :

$B_{IR^{2}}=$ { $e_{1},e_{2}$ }

Being $B_{IR^{2}}$ the cannonic base of $IR^{2}$

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

$T(\left[\begin{array}{c}1&0\end{array}\right])=\left[\begin{array}{c}4&5\end{array}\right]$ (Data of the problem)

$T(\left[\begin{array}{c}0&1\end{array}\right])=\left[\begin{array}{c}-2&7\end{array}\right]$ (Data of the problem)

Writing the matrix A :

$A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]$

Now with the matrix A we can find the image of $\left[\begin{array}{c}4&-4\\\end{array}\right]$ such as :

$T(x)=Ax$ ⇒

$T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]$

We found out that the image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is the vector $\left[\begin{array}{c}24&-8\end{array}\right]$

3 0

2 years ago