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almond37 [142]
3 years ago
8

The monthly worldwide average number of airplane crashes of commercial airlines is 3.5. What is the probabil- ity that there wil

l be (a) at least 2 such accidents in the next month; (b) at most 1 accident in the next month
Mathematics
1 answer:
Levart [38]3 years ago
3 0

Answer:

Step-by-step explanation:

We would apply the formula for poisson distribution which is expressed as

P(x = r) = (e^- µ × µ^r)/r!

Where

µ represents the mean of the theoretical distribution.

r represents the number of successes of the event.

From the information given,

µ = 3.5

a)

For the probability that there will be at least 2 such accidents in the next month, it is expressed as

P(x ≥ 2) = 1 - P(x < 2)

P(x < 2) = P(x = 0) + P(x = 1)

Therefore,

P(x = 0) = (e^- 3.5 × 3.5^0)/0!

P(x = 0) = (e^- 3.5 × 1)/1

P(x = 0) = 0.03

P(x = 1) = (e^- 3.5 × 3.5^1)/1!

P(x = 1) = (e^- 3.5 × 3.5)/1

P(x = 1) = 0.11

P(x < 2) = P(x = 0) + P(x = 1) = 0.03 + 0.11 = 0.14

P(x ≥ 2) = 1 - 0.14 = 0.86

b)

For the probability that there will be at most 1 accident in the next month, it is expressed as

P(x ≤ 1) = P(x = 0) + P(x = 1)

P(x = 0) = 0.03

P(x = 1) = 0.11

P(x ≤ 1) = 0.03 + 0.11 = 0.14

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Step-by-step explanation:

Comment

Expand the second and 3rd factors first. Then worry about the x.

Solution

x(x + 2)(x + 4)

<em>first</em>: x * x =  x^2

<em>Outside</em>: 4*x = 4x

<em>Inside</em>: 2*x = 2x

<em>Last:</em> 2*4 = 8

Combine

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