Answer:
the answer for apex is shift
Step-by-step explanation:
Answer:
The correct options are:
- g(x) is shifted three units higher than f(x).
- g(x) has a period that is half the period of f(x).
Step-by-step explanation:
We have to compare the graphs of the function:

and 
We have to select the correct options among the following:
As we know that the period of sine function is 2π.
i.e. Period of function f(x) is: 2π.
The period of sin(2 x) is π.
Hence, the period of the function g(x) function is π.
- Hence, the period of g(x) is half the period of f(x).
- Also we could observe that g(x) is shifted 3 units upward.
2.8.1

By definition of the derivative,

We have

and

Combine these fractions into one with a common denominator:

Rationalize the numerator by multiplying uniformly by the conjugate of the numerator, and simplify the result:

Now divide this by <em>h</em> and take the limit as <em>h</em> approaches 0 :

3.1.1.
![f(x) = 4x^5 - \dfrac1{4x^2} + \sqrt[3]{x} - \pi^2 + 10e^3](https://tex.z-dn.net/?f=f%28x%29%20%3D%204x%5E5%20-%20%5Cdfrac1%7B4x%5E2%7D%20%2B%20%5Csqrt%5B3%5D%7Bx%7D%20-%20%5Cpi%5E2%20%2B%2010e%5E3)
Differentiate one term at a time:
• power rule


![\left(\sqrt[3]{x}\right)' = \left(x^{1/3}\right)' = \dfrac13 x^{-2/3} = \dfrac1{3x^{2/3}}](https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%5B3%5D%7Bx%7D%5Cright%29%27%20%3D%20%5Cleft%28x%5E%7B1%2F3%7D%5Cright%29%27%20%3D%20%5Cdfrac13%20x%5E%7B-2%2F3%7D%20%3D%20%5Cdfrac1%7B3x%5E%7B2%2F3%7D%7D)
The last two terms are constant, so their derivatives are both zero.
So you end up with

Answer:
-.095
Step-by-step explanation:
Answer:
is that your dc lol
Step-by-step explanation: