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MissTica
4 years ago
8

Tim's bank contains quarters, dimes and nickels. He has 3 more dimes than quarters and 6 fewer nickels than quarters. If he has

63 coins, write and solve an equation for how many quarters Tim has.
Mathematics
1 answer:
Artist 52 [7]4 years ago
8 0
(x - 3) + (x - 6) + x = 63
x - 3 + x - 6 + x = 63
Combine like terms
3x - 9 = 63
Isolate the constant
3x - 9 + 9 = 63 + 9
3x = 72
Isolate the viable
3x / 3 = 72 / 3
x = 24
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The perimeter of a square is 56cm. What is the approximate length of its diagonal?
gogolik [260]

To find the answer, we can use the Pythagoras theorem, where:

\sqrt{a^{2}+ b^{2} } =c^{2}

Where a and b is the side length and c is the diagonal.

In this case:

\sqrt{56^{2} +56^{2} } \\ =\sqrt{6272} \\ =79.19596... \\ =79.2(correct to 3 sig. fig.)

Therefore, the answer is 79.2cm

Hope it helps!

6 0
3 years ago
SOMEONE PLEASE HELP THANK YOU SOOO MUCH ILY!!!
Mashutka [201]

Answer:

the green one

(1,3)

Step-by-step explanation:

i hope thai help!

5 0
3 years ago
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X/5 + 7 = 16 X= answer​
Debora [2.8K]

Step-by-step explanation:

x/5 + 7 = 16

x/5 = 16 - 7

x/5 = 9

x = 9×5

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6 0
4 years ago
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The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
If 8n + 25 = 65, then n is <br> a. 5. <br> 648. <br> less than <br> of 45 is <br> b. 10. <br> C. 40.
Monica [59]
8n+25=65
-25
8n=40
n=5 (answer choice a)
5 0
3 years ago
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