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Natali [406]
3 years ago
6

Which of the functions below could have created this graph?

Mathematics
1 answer:
svet-max [94.6K]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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The exact answer is 2,165.846153846154
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5 0
2 years ago
The length of a picture frame is (8u - 12) inches. It’s width is 3/4 of its length. Express the width of the picture frame in te
dezoksy [38]
3/4(8u-12)..................
7 0
3 years ago
PLZ ANSWER: A sandwich store charges a $10 delivery fee and $4.50 for each sandwich which is the total cost language and deliver
Irina-Kira [14]
Answer

$37

Explanation

it costs $4.50 per sandwich so you multiply that by 6 which gets you $27. then you add the delivery fee ($10) to that and you get $37

hope this helps!!
6 0
3 years ago
find the parametric equations for the line of intersection of the two planes z = x + y and 5x - y + 2z = 2. Use your equations t
Kaylis [27]

Answer:

You didn't give the points in which you want the parametric equations be filled, but I have obtained the parametric equations, and they are:

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

Step-by-step explanation:

If two planes intersect each other, the intersection will always be a line.

The vector equation for the line of intersection is given by

r = r_0 + tv

where r_0 is a point on the line and v is the vector result of the cross product of the normal vectors of the two planes.

The parametric equations for the line of intersection are given by

x = ax, y = by, and z = cz

where a, b and c are the coefficients from the vector equation

r = ai + bj + ck

To find the parametric equations for the line of intersection of the planes.

x + y - z = 0

5x - y + 2z = 2

We need to find the vector equation of the line of intersection. In order to get it, we’ll need to first find v, the cross product of the normal vectors of the given planes.

The normal vectors for the planes are:

For the plane x + y - z = 0, the normal vector is a⟨1, 1, -1⟩

For the plane 5x - y + 2z = 2, the normal vector is b⟨5, -1, 2⟩

The cross product of the normal vectors is

v = a × b =

|i j k|

|1 1 -1|

|5 -1 2|

= i(2 - 1) - j(2 + 5) + k(-1 - 5)

= i - 7j - 6k

v = ⟨1, -7, -6⟩

We also need a point on the line of intersection. To get it, we’ll use the equations of the given planes as a system of linear equations. If we set z = 0 in both equations, we get

x + y = 0

5x - y = 2

Adding these equations

5x + x + y - y = 2 + 0

6x = 2

x = 1/3

Substituting x = 1/3 back into

x + y = 0

y = -1/3

Putting these values together, the point on the line of intersection is

(1/3, -1/3, 0)

r_0= (1/3) i - (1/3) j + 0 k

r_0​​ = ⟨1/3, -1/3, 0⟩

Now we’ll plug v and r_0​​ into the vector equation.

r = r_0​​ + tv

r = (1/3)i - (1/3)j + 0k + t(i - 7j - 6k)

= (1/3 + t) i - (1/3 + 7t) j - 6t k

With the vector equation for the line of intersection in hand, we can find the parametric equations for the same line. Matching up r = ai + bj + ck with our vector equation,

r = (1/3 + t) i + (-1/3 - 7t) j + (-6t) k

a = (1/3 + t)

b = (-1/3 - 7t)

c = -6t

Therefore, the parametric equations for the line of intersection are

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

3 0
3 years ago
Let HH represent the number of hummingbirds and SS represent the number of sunbirds that must pollinate the colony so it can sur
Nikitich [7]

Answer: 7

Step-by-step explanation:

Here the given inequality that shows the number of humming birds(H) and the number of sunbirds(S)  that must pollinate the colony so it can survive until next year,

6 H + 4 S > 74

If This year, 8 hummingbirds pollinated the colony.

By putting H=8 in the above inequality,

We get,

6× 8 + 4 S > 74

⇒ 48 + 4 S > 74

⇒ 4 S > 26

⇒ S > 6.5

Hence the least number of sunbirds is 7.

7 0
3 years ago
Read 2 more answers
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