Hello :
f(x) = sin²(x) +cos(x)
the dirivate is : f'(x) = 2sin(x) cos(x) -sin(x) because :
( sin²(x) )' = 2sin(x) cos(x) and (cos(x))' = - sin(x)
f'(x) = 0 : sin(x) (2cos(x) - 1) = 0
sin(x) = 0 : x = k <span>π k in Z
</span>2cos(x) - 1 =0 : 2cos(x) =1
cos(x) = 1/2 = cos( π /3)
x = π /3 +2k π or x = - π /3 +2k π
in intervall : <span> <span>[0
, 2π] :
k=0 : x= 0 f(0) = 1 ( </span></span>minimum<span>)
</span>k=1 : x = π f(π) = -1 (<span>minimum)
x= </span> π /3 f ( π /3 ) = 1.25 ( <span>maximum)</span>
Answer:
5 snack bags and 6 juice boxes.
Step-by-step explanation:
The least common multiple of 12 and 10 is 60. If he buys 5 snack bags and 6 juice boxes, he will have 60 of each. 12 goes into 60 5 times, and 10 goes into 60 6 times.
Answer:
Affects the width of a confidence interval, as the margin of error is a function of the sample standard deviation.
Step-by-step explanation:
When we have the standard deviation for the sample, the t-distribution is used to solve the question.
It does not affect the center of the interval, which is a function only of the sample mean.
Width of a confidence interval:
The width of a confidence interval is a function of the margin of error, which is:
In which s is related to the sample standard deviation. Thus, since s and M are directly proportional, a higher standard deviation makes the interval wider, lower standard deviation makes the interval narrower, and thus, the sample standard deviation affects the the width of a confidence interval.
Yes the slope of a vertical line is parallel.
Parallel lines never intersect each other.
Y-axis is a vertical axis cartesian coordinate plane.
All vertical lines would be parallel to y-axis.
Because all vertical lines would have same slope, that is undefined slope.
Therefore, <em>all vertical lines would be parallel lines.</em>
So, we can finally say that it is possible for vertical lines to be parallel.
I don't have mlㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
