A candle burns at a constant rate once it is lit. The height of the candle is 250

Mathematics

1 answer:

Ierofanga [76]2 years ago

7 0

It burned down 20mm in 20 minutes. So the height so the change in height of the candle per minute in -1 mm

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You have a credit card with a balance of $754.43 at a 13.6% APR. You have $300.00 available each month to save or pay down your

pochemuha

<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]

where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.

We require B(n) = 0...i.e. balance of 0 after n months.

so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]

Then, with some algebraic juggling we get:

n = -[log(1 - (Ai/P)]/log(1 + i)

Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43

Also, i = (13.6/100)/12 => 0.136/12 per month

i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)

so, n = 4.15 months...i.e. 4 payments + remainder

b) Now we have A = $754.43 - $300 = $454.43 so,

n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)

so, n = 1.54 months...i.e. 1 payment + remainder
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8 0

3 years ago

The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.

motikmotik

Answer:

$\text{The width of rectangle}=9x\text{ meters}$

Step-by-step explanation:

We have been given that the rectangle has an area of $18x^3$ square meters and a length of $2x^{2}$ . We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

$\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}$

$\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}$

$\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}$

Upon substituting our given values in above formula we will get,

$\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}$

$\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}$

Using exponent rule for quotient $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\text{The width of rectangle}=9x^{3-2}\text{ meters}$

$\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}$

Therefore, width of our given rectangle will be 9x meters.

3 0

2 years ago

a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora

Arada [10]

Answer:

The mass of each passenger is 550 kg.

The mass of front decoration is 200 Kg.

Step-by-step explanation:

Given : A roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decoration and only 4 passenger cars, it has a mass of 2400 kg.

To find : What is the mass of the decoration and of each passenger car?

Solution :

Let the mass of each passenger is x.

Let the mass of front decoration is y.