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Andrew [12]
2 years ago
13

It was a very freaky weather day. The temperature started out at 9 in the morning and went to -13 at noon. It stayed at that tem

perature for six hours and then it rose 7. How far below the freezing point (0) was the temperature at 6pm?
Mathematics
1 answer:
Lady_Fox [76]2 years ago
4 0

Answer:

6

Step-by-step explanation:

At 6pm, which is 6 hours after the noon, the temperature was:

-13 + 7

= -6

6 below the freezing point

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I need help with my math
mrs_skeptik [129]

Answer:

42

Step-by-step explanation:

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3 years ago
Draw 4 non collinear points
harina [27]
I don't know if you have to do this on a graph, or just on a blank space. But, noncollinear means, "not on the same line". So, if you were to draw four points in a blank spot on a piece of paper, just draw four points in random places, making sure they aren't all directly in line with eachother. For a graph, use points like: (-6,2), (5,7), (8,3), and (1,-3). Notice that none of them have the same x or y coordinates, so they can't possibly be collinear.
4 0
3 years ago
The measure of one of the small angles of a right triangle is 15 less than twice the measure of the other small angle. Find the
gulaghasi [49]

Answer:

35° and 55°

Step-by-step explanation:

The sum of the angles of a right rectagle is 180°, with a right angle of 90°.

The tell us that A = 2B-15, so:

180° = 90° + A + B

180° = 90° + 2B - 15 + B

180° - 90° + 15 = 2B + B

105° = 3B

B = 105°/3 = 35°

Now, let's find A:

A = 180° - 90° - 35° = 55°

7 0
2 years ago
!!!!!!!!!!!!!!!!!!!!!!
bezimeni [28]

Answer:

x = 55

Step-by-step explanation:

To find the value of x

3x - 35 = 130 (vertically opposite angles are equal)

3x = 130 +35

3x = 165

x = 165/3

x = 55

8 0
2 years ago
Read 2 more answers
1) El ritmo cardíaco de un gato ( en latidos por minuto) es función lineal de su temperatura corporal (en grados Celsius). En co
olga55 [171]

Answer:

y=10x-170

Step-by-step explanation:

This problem can be modeled by a linear function, where we have two points (37°C, 200) and (32°C, 150).

Notice that the temperature is the independent variable, because the heartbeat of the cat won't change the temperature, it works in the opposite way.

First, let's find the constant ratio of change.

m=\frac{150-200}{32-37}=\frac{-50}{-5}=10

This means the hearbeat of the car changes 10 pulses per minute each 1 celsius degree.

Now, we use the point slope formula to find the equation

y-y_{1} =m(x-x_{1} )\\y-150=10(x-32)\\y=10x-320+150\\y=10x-170

Theerefore, the function that represents this situation is

y=10x-170

Where x represents temperature and y represents hearbeats.

6 0
3 years ago
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