Answer:
1) Consider that he makes $1189 every two weeks engaged with work
2) An estimate of the opportunity cost of going on the fishing trip is $1450 in two weeks
3). If he decides to buy the truck, he has to work for about 7 weeks before going on the fishing trip
Step-by-step explanation:
From the given data
Total revenue from lawn mowing per year = 35 × 4× 5×20 = $1400
Similarly total operating costs = $2110
Total profit per annum = $11890
However total revenue per every 2 weeks = $1189
To buy the truck, sell his and go on the fishing trip it will cost = 5200-1500+250 =$3950 hence he has to work for about 6.64 or approximately 7 weeks before going on the fishing trip
2) Opportunity cost will factor in the cost of having someone work for him while away
The cost is = $250 + $120/day
Hence in two weeks it will cost him $1450
3) He has to work for about 7 weeks to be able to afford the truck
Answer:
3 / 8
Step-by-step explanation:
From the tree diagram provided :
Required outcome = atleast two consecutive tails :
(HTT) ; (TTH) ; (TTT) = 3
TOTAL POSSIBLE OUTCOMES = 8
PROBABILITY = REQUIRED OUTCOME / TOTAL POSSIBLE OUTCOMES
HENCE ;
P(ATLEAST TWO TAILS IN A ROW) = 3 / 8
(y + z)³ ( i believe you were trying to do the expression to the power of 3)
(y + z)³ = (y + z)(y + z)(y + z)
Use the FOIL method:
(y + z)(y + z) = y² + yz + yz + z²
Simplify
y² + 2yz + z²
plug in the answer gotten back into the expression
(y² + 2yz + z²)(y + z)
FOIL again, distribute each number to the other.
y²(y) = y³
y(2yz) = 2y²z
y(z²) = yz²
y²(z) = y²z
2yz(z) = 2yz²
z(z²) = z³
2y²z + 2yz² + y³ + z³ + y²z + yz²
Simplify: add all like variables
2y²z + y²z = 3y²z
2yz² + yz² = 3yz²
3y²z + 3yz² + y³ + z³ is your answer, or <span>y^3 + 3y^2z + 3yz^2 + z^3
hope this helps</span>
