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ira [324]
2 years ago
15

Find the slope of the line passing through the points -2,7 and -6,3

Mathematics
1 answer:
Helga [31]2 years ago
6 0

Answer: the slope is 1

Step-by-step explanation:

m = y2 - y1 / x2 - x1

m = 7-3 / -2+6

m = 4/4

m=1

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A pediatrician wishes to study how the average weight Y (in kilograms) of children changes during the first year of life. He plo
leonid [27]

Answer:

Answer is option a ) 0.53

Step-by-step explanation:

slope = r*\frac{s_y}{s_x}

Given that a pediatrician wishes to study how the average weight Y (in kilograms) of children changes during the first year of life. He plots these averages versus the age X (in months) and decides to fit a least-squares regression line to the data with X as the explanatory variable and Y as the response variable.

He finds  the following quantities:

r = correlation between X and Y= 0.84

x = mean of the values of X = 5.69

y = mean of the values of Y = 6.26

S_x = standard deviation of the values of X = 3.23

s_y = standard deviation of the values of Y = 2.04

Using the formula for slope given above substitute to get

slope = 0.84*\frac{2.04}{3.23} \\=0.5305

round off to 0.53

Answer is option a ) 0.53

3 0
3 years ago
I need help no ilnks please and thank you
Elza [17]

Answer:

yep

Step-by-step explanation:

nice

8 0
3 years ago
How many more is the 3 in 43021.4 then the 3 in 9760
svet-max [94.6K]

this answer is not possible there is no 3 in 9760

3 0
3 years ago
I really need help in this plz help if ur here ​
vazorg [7]

Answer:

watch a video or use a hint.

Step-by-step explanation:

it say it.

4 0
3 years ago
How to Solve this?? <br> Please provide steps for remembrance.
belka [17]

When a problem asks g\circ f, it really means: g(f(x))

So, whenever you have a function say f(x), and you want to find f(1), you plug 1 wherever you see an x. This problem is no differen, except we're plugging in an f(x) wherever we see an x in g(x) to get:

g(f(x))=f(x)^2+16 \implies\\ g(f(x))=(\sqrt{x})^2+16 \implies\\ g(f(x))=x+16

8 0
4 years ago
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