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Dima020 [189]
3 years ago
12

look at pic 10 pts will mark brainilest hhhionnia

Mathematics
1 answer:
-BARSIC- [3]3 years ago
7 0
30 because 18 and the plain goes into 12 which is 30
I think
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Find the value of APD angle.
Maslowich

Answer:

135

Step-by-step explanation:

angle APB is an alternate interior angle to DBC and line DB is supplementary

APD=180-45=135

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Consider the enlargement of the pentagon. A small pentagon has a bottom side length of x centimeters and left side length of 7 c
LuckyWell [14K]

When the pentagon is drawn to scale then its value of x will be x=3.3 cm

<h3>What is the pentagon?</h3>

The pentagon is defined as the shape having five sides connected together.

Now it is given in the question that

For small pentagone

Bottom =x

left =7 cm

For larger pentagone

Bottom=7cm

left=15cm

Now since the pentagon is actually dilated from its size to the new bigger size. It means that the equivalent ratio of both the pentagons will be equal.

For smaller pentagon

\rm Equivalent \ Ratio = \dfrac{Bottom}{Left} =\dfrac{x}{7}

For bigger pentagon

\rm Equivalent \ Ratio = \dfrac{Bottom}{Left} =\dfrac{7}{15}

Since both, the ratio is the same

\dfrac{x}{7} =\dfrac{7}{15}

x=\dfrac{49}{15} =3.3\ cm

Thus the pentagon is drawn to scale than its value of x will be x=3.3 cm

To know more about Pentagone follow

brainly.com/question/4804571

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How many tiles each 30cm by 30cm will be needed for floor​
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Read 2 more answers
In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6 years according to the U.S. Depa
marissa [1.9K]

Answer:

The <em>95% confidence interval</em> for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Step-by-step explanation:

The <em>confidence interval</em> of the mean is given by the next formula:

\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}} [1]

We already know (according to the U.S. Department of Justice):

  • The (population) standard deviation for this case (mean age of an inmate on death row) has a standard deviation of 9.6 years (\\ \sigma = 9.6years).
  • The number of observations for the sample taken is \\ n = 32.
  • The sample mean, \\ \overline{x} = 38.9 years.

For \\ z_{1-\frac{\alpha}{2}}, we have that \\ \alpha = 0.05. That is, the <em>level of significance</em> \\ \alpha is 1 - 0.95 = 0.05. In this case, then, we have that the <em>z-score</em> corresponding to this case is:

\\ z_{1-\frac{\alpha}{2}} = z_{1-\frac{0.05}{2}} = z_{1-0.025} = z_{0.975}

Consulting a cumulative <em>standard normal table</em>, available on the Internet or in Statistics books, to find the z-score associated to the probability of, \\ P(z, we have that \\ z = 1.96.

Notice that we supposed that the sample is from a population that follows a <em>normal distribution</em>. However, we also have a value for n > 30, and we already know that for this result the sampling distribution for the sample means follows, approximately, a normal distribution with mean, \\ \mu, and standard deviation, \\ \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}.

Having all this information, we can proceed to answer the question.

Constructing the 95% confidence interval for the current mean age of death-row inmates

To construct the 95% confidence interval, we already know that this interval is given by [1]:

\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

That is, we have:

\\ \overline{x} = 38.9 years.

\\ z_{1-\frac{\alpha}{2}} = 1.96

\\ \sigma = 9.6 years.

\\ n = 32

Then

\\ 38.9 \pm 1.96*\frac{9.6}{\sqrt{32}}

\\ 38.9 \pm 1.96*\frac{9.6}{5.656854}

\\ 38.9 \pm 1.96*1.697056

\\ 38.9 \pm 3.326229

Therefore, the Upper and Lower limits of the interval are:

Upper limit:

\\ 38.9 + 3.326229

\\ 42.226229 \approx 42.23 years.

Lower limit:

\\ 38.9 - 3.326229

\\ 35.573771 \approx 35.57 years.

In sum, the 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Notice that the "mean age of an inmate on death row was 40.7 years in 2002", and this value is between the limits of the 95% confidence interval obtained. So, according to the random sample under study, it seems that this mean age has not changed.

7 0
3 years ago
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