Answer:
- secant slopes: -213.5, -187, -145, -113, -85
- tangent slope: -166
Step-by-step explanation:
A) the slope values you have put in your problem statement are correct. As you know, they are computed from ...
(change in gallons)/(change in time)
where the reference point for changes is P. Using the first listed point Q as an example, the secant slope is ...
(3410 -1275)/(5 -15) = 2135/-10 = -213.5 . . . . gallons per minute
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B) The average of the secant slopes for points Q adjacent to P is ...
(-187 +(-145))/2 = -332/2 = -166 . . . . gallons per minute
The tangent slope at point P is estimated at -166 gpm.
Answer: x = 10
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The two blue chords are equally distant from the center. This is shown by the segments with single tick marks. These segments are 3.5 units long.
The bottom blue chord is 10 units long because half of it is 5 units.
Since the chords are the same distance away from the center, this means that the blue chords are equal in length. Both blue chords are 10 units long.
Calll x the smaller negative number.
The larger number will be x + 8
The product will be x(x+8) = 308
An the equation:
x^2 + 8x = 308
x^2 + 8x - 308 =0
If you solve that equation you will get x = -22 and x = 14.
The result that you are looking is the negative, x = -22.
The larger number is -22 + 8 = -14.
(-22)*(-14) = 308
Answer: x^2 + 8x - 308 =0
Answer:
2x^7
Step-by-step explanation:
2x^4 × x^3 =
= 2x^(4+3)
= 2x^7
55% is crackers if the 11 is crackers
