Find the sum of the arithmetic series

Which of the following options have the same value as 30\%30%30, percent of 818181?

Nataly_w [17]

Answer:

Option B is correct = $0.3 \times 81$

Step-by-step explanation:

The complete question is: Which of the following options have the same value as 30% of 81?

Group of choices is:

(A) $\frac{30}{100}\times 81 \times 100$

(B) $0.3 \times 81$

(C) $0.03 \times 81$

(D) $\frac{3}{10}\times 81 \times 10$

(E) $30 \times 81$

Now, the expression given to us is 30% of 81.

Simplifying the above expression we get;

30% of 81 = $\frac{30}{100} \times 81$

= $\frac{3}{10} \times 81$ = $0.3 \times 81$

Now, we will solve each of the given options and then see which option matches with our calculation.

Option (A) is given;

$\frac{30}{100}\times 81 \times 100$ = $30 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (B) is given;

$0.3 \times 81$

This matches with our answer, so this option is correct.

Option (C) is given;

$0.03 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (D) is given;

$\frac{3}{10}\times 81 \times 10$ = $3 \times 81$

This doesn't match with our answer, so this option is not correct.

Option (E) is given;

$30 \times 81$

This doesn't match with our answer, so this option is not correct.

6 0

3 years ago

1. Find two numbers with a common factor of 3 only.

Mnenie [13.5K]

Answer:

All numbers can be written as a product of the prime numbers that conform them.

A) Find two numbers with a common factor of 3 only.

for example:

2*3 = 6

7*3 = 21

Both numbers have the factor 3 in them, and because the other two numbers are primes, we can be sure that the 3 is the only common factor.

B) Write a pair of numbers with a common factor of 2, 3 and 6.

Here we can write:

2*3*2 = 12

3*2*5 = 30

Those two numbers have the common factors 6, 2 and 3.

C) Write a pair of numbers with common factors of 3, 6 and 9.

3*2*3 = 18 (has the factors 2, 3, 3*2 = 6, 3*3 = 9)

-3*2*6 = -36

Both have the common factors 3, 6 and 9 (and they share more common factors like 2, this happens because 6 = 3*2, so if 6 is a common factor, 2 also must be)

8 0

3 years ago

SOMEONE PLS HELP QUICK WILL GIVE BRAiNLIEST

skad [1K]

Answer:

1. x^2-9x+18

2. 2x^2-4x-16

3. 3x^2-19x-14

4. 6x^2 +14x + 8

Step-by-step explanation:

1. (x-3)(x-6)

x^2 - 6x - 3x +18 = x^2-9x+18

2. (2x+4)(x-4)

2x^2-8x+4x-16 = 2x^2-4x-16

3. (x-7)(3x+2)

3x^2+2x-21x-14 = 3x^2-19x-14

4. (3x+4)(2x+2)

6x^2+6x+8x+8 = 6x^2 +14x + 8

6 0

3 years ago

Need help #1. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.

Rufina [12.5K]

Answer:

B

Step-by-step explanation:

We are given that x and y are functions of time t such that x and y is a constant. So, we can write the following equation:

$x(t)+y(t)=k,\text{ where $k$ is some constant}$

The rate of change of x and the rate of change of y with respect to time t is simply dx/dt and dy/dt, respectively. So, we will differentiate both sides with respect to t:

$\displaystyle \frac{d}{dt}\Big[x(t)+y(t)\Big]=\frac{d}{dt}[k]$