Find the mean and median of the data set. 3, 5, 6, 2, 10, 9, 7, 5, 11, 6, 4, 2, 5, 4

Lin's father is paying for a $20 meal. He has a 30%-off coupon for the meal. After the discount, a 8% sales tax is applied.

Airida [17]

Answer:

15.12

Step-by-step explanation:

Cost of meal = $20

Discount (coupon) = 30%

Amount of discount = 30% of $20

= 30/100 * 20

= 0.3 * 20

= $6

Amount paid after discount= initial cost of meal - discount

= $20 -$6

= $14

Sales tax =8%

Amount of sales tax = 8% of $14

= 8/100 * 14

= 0.08 * 14

= $1.12

Total amount paid = Amount paid after discount + Amount of sales tax

= $14 + $1.12

= 15.12

8 0

2 years ago

HEY PLEASE HELP

pshichka [43]

The answer is $50.45 I think

3 0

3 years ago

Read 2 more answers

Anyone please help me

Ulleksa [173]

Answer:

D

Step-by-step explanation:

The perpendicular equation can be found by getting the reciprocal of the slope then multiplying it by -1. The slope is the "m" value of y=mx+b; in this case, the slope is $\frac{2}{5}$ .

To find out if it is C or D, you plug in the x value given in the equation (2) and see if it equals the y value given in the equation (-2). C is incorrect, which means that D is correct.

8 0

2 years ago

Read 2 more answers

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago

The scores on a test are normally distributed with a mean of 78 and a standard deviation of 13. Find the score that is 2 standar

Veronika [31]

Answer:

52

Step-by-step explanation:

Given that :

Mean (m) = 78

Standard deviation (s) = 13

Score that is 2 standard deviations below the mean

Using the relation :

Zscore = (x - m) / s

2 standard deviations below the mean means a Zscore of - 2

Hence,

-2 = (x - 78) / 13

Cross multiply

-2 * 13 = x - 78

-26 = x - 78

x = - 26 + 78

x = 52

Score which is 2 standard deviations below the mean is 52

4 0

3 years ago