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Andrei [34K]
3 years ago
13

What is the value of x in the geometric sequence x,2,-1/2,...?

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0

Answer:

x = 4 1/2

Step-by-step explanation:

To get to minus 1/2 from plus 2 you would subtract 2 1/2 from 2.

To arrive at x you would add 2 1/2 to 2.

The result is a progression of:  4 1/2, 2, - 1/2

(4 1/2 minus 2 1/2 = 2; 2 minus 2 1/2 = - 1/2)

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0.11 as a fraction and in the simplest form
vovangra [49]
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A gym employee is paid monthly. After working for three months, he earned $4,500. To determine how much money he will make over
Bogdan [553]
I don’t know your question but he would get 1500 each month so he gets 9000 over sixth months
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A part-time landscaper made $8996.32 last year. if she claimed herself as an exemption for $3650 and had a $5700 standard deduct
Andrej [43]

Answer:

$0

Step-by-step explanation:

A part-time landscaper made $8996.32 last year.

She claimed herself as an exemption for $3650 and had a $5700 standard deduction

Exemption means not subject to taxation.

Deduction means taking some amount of your income for the year, and not have to pay taxes on it.

So, 8996.32-(3650+5700)

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So, her taxable income last year was $0.

Thus Option D is correct.

7 0
3 years ago
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The plane x + y + z = 12 intersects paraboloid z = x^2 + y^2 in an ellipse.(a) Find the highest and the lowest points on the ell
emmasim [6.3K]

Answer:

a)

Highest (-3,-3)

Lowest (2,2)

b)

Farthest (-3,-3)

Closest (2,2)

Step-by-step explanation:

To solve this problem we will be using Lagrange multipliers.

a)

Let us find out first the restriction, which is the projection of the intersection on the XY-plane.

From x+y+z=12 we get z=12-x-y and replace this in the equation of the paraboloid:

\bf 12-x-y=x^2+y^2\Rightarrow x^2+y^2+x+y=12

completing the squares:

\bf x^2+y^2+x+y=12\Rightarrow (x+1/2)^2-1/4+(y+1/2)^2-1/4=12\Rightarrow\\\\\Rightarrow (x+1/2)^2+(y+1/2)^2=12+1/2\Rightarrow (x+1/2)^2+(y+1/2)^2=25/2

and we want the maximum and minimum of the paraboloid when (x,y) varies on the circumference we just found. That is, we want the maximum and minimum of  

\bf f(x,y)=x^2+y^2

subject to the constraint

\bf g(x,y)=(x+1/2)^2+(y+1/2)^2-25/2=0

Now we have

\bf \nabla f=(\displaystyle\frac{\partial f}{\partial x},\displaystyle\frac{\partial f}{\partial y})=(2x,2y)\\\\\nabla g=(\displaystyle\frac{\partial g}{\partial x},\displaystyle\frac{\partial g}{\partial y})=(2x+1,2y+1)

Let \bf \lambda be the Lagrange multiplier.

The maximum and minimum must occur at points where

\bf \nabla f=\lambda\nabla g

that is,

\bf (2x,2y)=\lambda(2x+1,2y+1)\Rightarrow 2x=\lambda (2x+1)\;,2y=\lambda (2y+1)

we can assume (x,y)≠ (-1/2, -1/2) since that point is not in the restriction, so

\bf \lambda=\displaystyle\frac{2x}{(2x+1)} \;,\lambda=\displaystyle\frac{2y}{(2y+1)}\Rightarrow \displaystyle\frac{2x}{(2x+1)}=\displaystyle\frac{2y}{(2y+1)}\Rightarrow\\\\\Rightarrow 2x(2y+1)=2y(2x+1)\Rightarrow 4xy+2x=4xy+2y\Rightarrow\\\\\Rightarrow x=y

Replacing in the constraint

\bf (x+1/2)^2+(x+1/2)^2-25/2=0\Rightarrow (x+1/2)^2=25/4\Rightarrow\\\\\Rightarrow |x+1/2|=5/2

from this we get

<em>x=-1/2 + 5/2 = 2 or x = -1/2 - 5/2 = -3 </em>

<em> </em>

and the candidates for maximum and minimum are (2,2) and (-3,-3).

Replacing these values in f, we see that

f(-3,-3) = 9+9 = 18 is the maximum and

f(2,2) = 4+4 = 8 is the minimum

b)

Since the square of the distance from any given point (x,y) on the paraboloid to (0,0) is f(x,y) itself, the maximum and minimum of the distance are reached at the points we just found.

We have then,

(-3,-3) is the farthest from the origin

(2,2) is the closest to the origin.

3 0
3 years ago
A distribution has a mean of 16 and a standard deviation of 6. What is the Z score that corresponds with 34?
Brrunno [24]

Answer:

Z = 3

Step-by-step explanation:

In a normal distribution, the Z score that corresponds with a data point x is calculated using the formula;

Z=\frac{x-mean}{standard deviation}

For the case given, the z score will be;

Z=\frac{34-16}{6}=3

7 0
3 years ago
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