<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
Answer:
12(3y+2x)
Step-by-step explanation:
In this question, we are asked to give an expression that represents the total cost of shorts for the players.
He is ordering 2 pairs of short and 3 shirts. Hence, per player, he would be spending the following:
2 pairs of shorts at x dollars each. Cost here is just $2x
3 shirts at y per one. Cost is $3y
Per player he is spending a total of 3y + 2x
Now, there are people to cater for. The total amount to spend will now be 12(3y + 2z )
Answer:
X= 8
Y= 130
(8, 130)
Step-by-step explanation:
I used a graphing calculator to see where the two equations intersected.
Hope this helped :)
Answer:
# red marbles = 25
# blue marbles = 7
Step-by-step explanation:
r + b = 32
r = 4 + 3b
substitute '4 + 3b' for 'r' in the 1st equation
4 + 3b + b = 32
4 + 4b = 32
4b = 28
b = 7
red = 32 - 7
r = 25
