Help if u may question 7 out of 15 helpp
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Answer: C (2,-3)
Explanation: (x1+x2/2),(y1+y2/2)
![\tt \: {5x}^{2} + 15x](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%20%20%7B5x%7D%5E%7B2%7D%20%20%2B%2015x)
Factor out 5x from the expression
![\tt \: 5x(x + 3)](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%205x%28x%20%2B%203%29)
11390625 that is what i got.<span> </span>
![\displaystyle\iint_R(9x-3y)(2x-y)\,\mathrm dA](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Ciint_R%289x-3y%29%282x-y%29%5C%2C%5Cmathrm%20dA)
![\begin{cases}u=x-3y\\v=2x-y\end{cases}\implies\begin{cases}x=\frac{3v-u}5\\y=\frac{v-2u}5\end{cases}\implies\mathrm dA=|\det J|\,\mathrm du\,\mathrm dv](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Du%3Dx-3y%5C%5Cv%3D2x-y%5Cend%7Bcases%7D%5Cimplies%5Cbegin%7Bcases%7Dx%3D%5Cfrac%7B3v-u%7D5%5C%5Cy%3D%5Cfrac%7Bv-2u%7D5%5Cend%7Bcases%7D%5Cimplies%5Cmathrm%20dA%3D%7C%5Cdet%20J%7C%5C%2C%5Cmathrm%20du%5C%2C%5Cmathrm%20dv)
where
is the Jacobian matrix for the transformation,
![J=\begin{bmatrix}u_x&u_y\\v_x&v_y\end{bmatrix}=\begin{bmatrix}-\dfrac15&\dfrac35\\\\-\dfrac25&\dfrac15\end{bmatrix}\implies|\det J|=\dfrac15](https://tex.z-dn.net/?f=J%3D%5Cbegin%7Bbmatrix%7Du_x%26u_y%5C%5Cv_x%26v_y%5Cend%7Bbmatrix%7D%3D%5Cbegin%7Bbmatrix%7D-%5Cdfrac15%26%5Cdfrac35%5C%5C%5C%5C-%5Cdfrac25%26%5Cdfrac15%5Cend%7Bbmatrix%7D%5Cimplies%7C%5Cdet%20J%7C%3D%5Cdfrac15)
We have
![9x-3y=8x+x-3y=\dfrac85(3v-u)+u=\dfrac{24v-3u}5](https://tex.z-dn.net/?f=9x-3y%3D8x%2Bx-3y%3D%5Cdfrac85%283v-u%29%2Bu%3D%5Cdfrac%7B24v-3u%7D5)
so that the integral is
![\displaystyle\frac1{25}\int_9^{10}\int_0^{10}(24v-3u)v\,\mathrm du\,\mathrm dv=\boxed{\frac{4051}5}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac1%7B25%7D%5Cint_9%5E%7B10%7D%5Cint_0%5E%7B10%7D%2824v-3u%29v%5C%2C%5Cmathrm%20du%5C%2C%5Cmathrm%20dv%3D%5Cboxed%7B%5Cfrac%7B4051%7D5%7D)
Answer:
what statement?
Step-by-step explanation: