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3 years ago

What is Japanese tradition?

2 answers:

6 0

The arts are an important part of Japanese life. ... Traditional arts and crafts such as the tea ceremony, flower arranging and dance that express Japan's cultural heritage are greatly valued and designated as 'living national treasures'. Japan's history has been defined too by its literature and poetry.

Ivanshal [37]3 years ago

3 0

Answer:

Sumo, judo and karate are traditional Japanese sports and baseball, soccer and rugby have been adopted from other cultures. Sumo is the national sport of Japan and to this day is primarily practiced only in Japan. Modern sumo was formed during the E d o era and little has changed since.

Explanation:

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3 years ago

2.36 LAB: Warm up: Variables, input, and casting (1) Prompt the user to input an integer, a double, a character, and a string, s

Westkost [7]

Answer:

The entire program is:

#include <iostream>

using namespace std;

int main() {

int userInt;

double userDouble;

char userChar;

string userString;

cout<<"Enter integer:"<<endl;

cin>>userInt;

cout<<"Enter double:"<<endl;

cin>>userDouble;

cout<<"Enter character:"<<endl;

cin>>userChar;

cout<<"Enter string:"<<endl;

cin>>userString;

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl;

cout<<endl;

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl;

cout<<endl;

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl<<userDouble<<" cast to an integer is "<<(int)userDouble;

return 0; }

The program in C language:

#include <stdio.h>

int main() {

int userInt;

double userDouble;

char userChar;

char userString[50];

printf("Enter integer: \n");

scanf("%d", &userInt);

printf("Enter double: \n");

scanf("%lf", &userDouble);

printf("Enter character: \n");

scanf(" %c", &userChar);

printf("Enter string: \n");

scanf("%s", userString);

printf("%d %lf %c %s\n", userInt, userDouble, userChar, userString);

printf("\n");

printf("%d %lf %c %s\n%s %c %lf %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt);

printf("\n");

printf("%d %lf %c %s\n%s %c %lf %d\n%lf cast to an integer is %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt, userDouble, (int)userDouble); }

Explanation:

Lets do the program step by step:

1) Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output those four values on a single line separated by a space:

Solution:

The program is:

#include <iostream> //to use input output functions

using namespace std; //to identify objects cin cout

int main() { //start of main method

//declare an integer, a double, a character and a string variable

int userInt; //int type variable to store integer

double userDouble; //double type variable to store double precision floating point number

char userChar; //char type variable to store character

string userString; //string type variable to store a string

cout<<"Enter integer:"<<endl; //prompts user to enter an integer

cin>>userInt; //reads the input integer and store it to userInt variable

cout<<"Enter double:"<<endl; //prompts user to enter a double type value

cin>>userDouble; //reads the input double value and store it to userDouble variable

cout<<"Enter character:"<<endl; //prompts user to enter a character

cin>>userChar; //reads the input character and store it to userChar variable

cout<<"Enter string:"<<endl; //prompts user to enter a string

cin>>userString; //reads the input string and store it to userString variable

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl; //output the values on a single line separated by space

So the output of the entire program is:

Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy

(2) Extend to also output in reverse.

Now the above code remains the same but add this output (cout) statement at the end:

cout<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt;

Now the output with the same values given as input is:

Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy

99 3.77 z Howdy Howdy z 3.77 99

(3) Extend to cast the double to an integer, and output that integer.

The rest of the code remains the same but add the following output (cout) statement in the end:

cout<<userDouble<<" cast to an integer is "<<(int)userDouble;

Now the output with the same values given as input is:

Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy Howdy z 3.77 99 3.77 cast to an integer is 3

3 0

3 years ago