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balu736 [363]
3 years ago
8

What is Japanese tradition?

Computers and Technology
2 answers:
aev [14]3 years ago
6 0
The arts are an important part of Japanese life. ... Traditional arts and crafts such as the tea ceremony, flower arranging and dance that express Japan's cultural heritage are greatly valued and designated as 'living national treasures'. Japan's history has been defined too by its literature and poetry.
Ivanshal [37]3 years ago
3 0

Answer:

Sumo, judo and karate are traditional Japanese sports and baseball, soccer and rugby have been adopted from other cultures. Sumo is the national sport of Japan and to this day is primarily practiced only in Japan. Modern sumo was formed during the E d o era and little has changed since.

Explanation:

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For an external usb hard drive attached to a computer, which is more suitable: a writethrough cache or a block cache
Charra [1.4K]

Disk access is way slower than memory access. Caching is a technique to improve the disk access time.  Block cache is a caching technique which reduces disk accesses time.  Here a portion of disk is bought to cache for reading and a modified blocks are first changed in cache but reflected in the disk at one go.  On the other hand with write through caching each modified block is written to cache and at the same time it is written to the disk.  Write- through caching requires more disk I/O so they can have a negative effect on the performance. 

6 0
3 years ago
Read 2 more answers
Write a program that asks the user to enter the amount s/he has budgeted for a month. The amount should be between 1000 and 2000
Elena-2011 [213]

Answer:

The program to this question can be given as:

Program:

  //import package for user input.

import java.util.*;      

//define class

public class Budget                      

{

public static void main(String [] a)            //define main method.

{

//creating Scanner class object.

Scanner ob =new Scanner(System.in);    

//define variable.      

double budgetamount=0, amountspent=0 ,difference=0,total=0,num=0 ;        

int count = 0;                            

System.out.println("How much have you budgeted for the month? :");        //print message.

budgetamount=ob.nextDouble();                             //taking input

       while(budgetamount != 0)           //checkig number greater then 4 digite.

       {

           budgetamount= budgetamount/10;        

           ++count;

       }

       if(count>4)                 //condition

       {

       System.out.println("enter each expense, then type -999 to quit: ");

       while(num!=-999)               //taking expense  

       {

       total=total+num;                 //totaling expense

       num=scan.nextDouble();                  

       }

       if(total<=budgetamount)           //condtion for over budget.

       {

       System.out.print("under budget:");         //print message

       System.out.print(budgetamount-total);

       }

       else

       {

       System.out.print("over budget:");              //for under budget

       System.out.print(total-budgetamount);

       }

       }

       else

       {

       System.out.println("not valid");        //message for number lessthen 4 digit.    

       }                                      

}

}

output:

How much have you budgeted for the month? : 1200.55.

enter each expense, then type -999 to quit: 365.89

556.90

339.98

-999

over budget:1262.77

Explanation:

The explanation of this program can be given as:

In the above program we import the package in that is used for scanner class. This class is used for the input from the user after input we use the while loop and if-else statement. The while loop is the entry control loop It is used for input validation and if-else is used for the checking condition. Then we insert expense that is inserted by the user. Then we calculate under-budgeted and over-budgeted by conditional statement that is if-else. and at the last we print it.

5 0
3 years ago
Select the correct answer.
goblinko [34]

Answer:

b

Explanation:

8 0
3 years ago
Part1) Given 3 integers, output their average and their product, using integer arithmetic.
Mrac [35]

Answer:

The program is as follows:

#include <iostream>

#include <iomanip>

using namespace std;

int main(){

   int num1, num2, num3;

   cin>>num1>>num2>>num3;

   cout << fixed << setprecision(2);

   cout<<(num1 + num2 + num3)/3<<" ";

   cout<<num1 * num2 * num3<<" ";

   return 0;

}

Explanation:

This declares three integer variables

   int num1, num2, num3;

This gets input for the three integers

   cin>>num1>>num2>>num3;

This is used to set the precision to 2

   cout << fixed << setprecision(2);

This prints the average

   cout<<(num1 + num2 + num3)/3<<" ";

This prints the product

   cout<<num1 * num2 * num3<<" ";

6 0
3 years ago
What usually happens at a police check? Do they just look up your name in their system?
sdas [7]

it depends on the kind of police check. like if its a road block type of check, they make sure everything is right. if you get pulled over you get your name ran in the system to check if you have warrents or warning and depends on what you get pulled over for, you could get a ticket or detained.

5 0
3 years ago
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