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Aleksandr-060686 [28]
3 years ago
13

5. What are the dimensions of a cylindrical container that holds 900 mL of chocolate milk?

Mathematics
1 answer:
ziro4ka [17]3 years ago
6 0
1 cubic meter is equal to 1000 liters. 900mL is equal to .9 liters therefore:
(1 cubic meter/1000L)*(.9L/x)=.0009cubic meters

900mL is .0009 cubic meters

The formula for cylinder is:
V=πr2h
.0009=πr2h.00014323944=rh


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Complete the solution of the equation. Find the value of y when x equals 8. 4x+9y=-14
Shtirlitz [24]

Y=-5.11111 how I solved it is in the picture attached

5 0
3 years ago
How can i calculate the growth rate of the values below
Grace [21]

Answer:

  12%

Step-by-step explanation:

The equation for the growth is ...

  f(t) = (initial value)×(growth multiplier per period)^(number of periods)

where the growth multiplier is often expressed as a percentage added to 1:

  multiplier = 1+r

  growth rate = r

__

This equation has two unknowns:

  • initial value
  • growth multiplier

In order to find these, you can make use of two of the supplied data points. I like to choose the ones that are farthest apart, as they tend to average out any errors due to rounding.

Clearly, the table tells you the initial value is 210. If you don't believe, you can put the numbers in the equation to see that:

  f(0) = (initial value)×(growth multiplier)^0

  210 = (initial value)×1

  (initial value) = 210

__

Using the last data point, we get ...

  f(7) = 210×(growth multiplier)^7

  464 = 210×(growth multiplier)^7 . . . . . . . . . fill in table value

  2.209524 = (growth multiplier)^7 . . . . . . .  divide by 210

You can solve this a couple of ways. My calculator is able to take the 7th root, so I can use it to find ...

  \sqrt[7]{2.209524}=\text{(growth multiplier)}\\1.119916\approx \text{(growth multiplier)}

Alternatively, you can use the 1/7 power:

  2.209524^(1/7) = (growth multiplier)

Another way to solve this is to use logarithms:

  log(2.209524) = 7×log(growth multiplier) . . . . . take the log

  log(2.209524)/7 = log(growth multiplier) . . . . . divide by 7

  0.04918553 ≈ log(growth multiplier)

  growth multiplier = 10^0.04918553 ≈ 1.11992 . . . . take the antilog

So, our growth multiplier is ...

  1 + r ≈ 1.11992

  r ≈ .11992 ≈ 12.0%

The rate of growth is about 12% in each period.

_____

Collapsing all of that to a single calculation:

  growth rate = (464/210)^(1/(7-0)) -1 ≈ 12.0%

8 0
3 years ago
(11x + 8) + (8x + 12) =27
Tju [1.3M]

Answer:

11x + 8 +8x +12 =27  (drop the parenthesis, there's no actual need for them)

19x +20 =27 (i combined like terms and then subtracted 20 from both sides)

19x = 7  (divide both sides by 19 to get x alone)

x= 7/19 or 0.36842105 (the answer)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 12 m. T
cestrela7 [59]

Answer:

The answer would be 251.2 for the side walk if the radius for the whole circle is 12 and the small circle's radius would be 8. Only for the answer with the 8 m and 12 m radius NOT the 11m and 9 m

The equation would be:

144 x 3.14 - 64 x 3.14 = 251.2

Step-by-step explanation:

First, you need to find out what the whole circle is:

The whole circle is 452.16

Then, find the inner circle :

8 x 8 x 3.14  

200.96

Last, subtract the whole by the inner:

452.16 - 200.96 = 251.2

hope this helps!

5 0
3 years ago
An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.
Tanya [424]

Answer:

98%  Confidencce Interval is ( 3030.6, 7467.4 )

Step-by-step explanation:

Given that:

Sample size n_1 = 71

Sample size n_2 = 31

Sample mean \overline x_1 = 41628

Sample mean x_2 = 36,379

Population standard deviation \sigma_1 = 4934

Population standard deviation \sigma_2 = 4180

At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02

Critical value at z_{0.02/2} = 2.33

The Margin of Error = z \times \sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2} }

= 2.33 \times \sqrt{\dfrac{4934^2}{71}+\dfrac{4180^2}{31} }

= 2.33 \times \sqrt{\dfrac{24344356}{71}+\dfrac{17472400}{31} }

= 2.33 \times \sqrt{906504.06 }

= 2218.40

The Lower limit = ( \overline x_1 - \overline x_2) - (Margin \ of \ error)

= ( 41628 - 36379 ) - ( 2218.40)

= 5249 - 2218.40

= 3030.6

The upper limit = ( \overline x_1 - \overline x_2) + (Margin \ of \ error)

= ( 41628 - 36379 ) + ( 2218.40)

= 5249 + 2218.40

= 7467.4

∴  98%  Confidencce Interval is ( 3030.6, 7467.4 )

5 0
3 years ago
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