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rodikova [14]
3 years ago
6

2

Mathematics
1 answer:
Rainbow [258]3 years ago
6 0

Answer:

tha anser us B

Step-by-step explanation:

it is very easy you just read the question carefully

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Find the distance between the points (-3, 11) and (5, 5).
marshall27 [118]
Formula for distance between two points:

d  = √((x₂-x₁)² + (y₂-y₁)²)

Let point 1 be (-3, 11) and point 2 be (5, 5)

Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.

d = √((x₂-x₁)² + (y₂-y₁)²)

   = √((5- -3)² + (5-11)²)

   = √((5+3)² + (5-11)²)

   = √((8)² + (-6)²)          8² = 8*8 = 64, (-6)² = -6*-6 = 36

   = √(64 + 36)

  = √(100)

  = 10

Distance = 10 units.
5 0
3 years ago
5
taurus [48]

Answer:

6 feet

Step-by-step explanation:

Since there are 8 bricks and each brick is 9 inches long, that is a total of 72 inches. Now, you need to convert it from inches to feet. Since 1 foot is 12 inches, we need to divide 72 by 12 to get the number of feet. 72 / 12 is equal to 6.

6 0
3 years ago
Is Joan read 74 pages in 4 hours how long will it take her to read 240 pages
kogti [31]

Answer:

It will take her 13 hours


5 0
3 years ago
Shows that n+1Cn= mCn-1 + mCn
ArbitrLikvidat [17]

Answer:

I think the Question is incorrect; the left hand side of the equation should be

m+1Cn

Step-by-step explanation:

4 0
2 years ago
Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr
Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

0.7278A(0) = A(0)e^{-10k}

e^{-10k} = 0.7278

\ln{e^{-10k}} = \ln{0.7278}

-10k = \ln{0.7278}

k = -\frac{\ln{0.7278}}{10}

k = 0.03177289938


Then

A(t) = A(0)e^{-0.03177289938t}

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

A(5) = 0.8531

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0
3 years ago
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