Answer:
If you want a simple average, you can add all the speeds you see and divide them by the number of how many they are.
So firstly you have to calculate the speed of the first point, which is:
20 miles/0.5 hour
That means: 40 miles/hour
That would be your first "speed"
Then you calculate all of them :speed1+speed2+speed3 = something.
As an example: 20miles/hr + 40miles/hr+0miles/hr = 60miles/hr
Then, you divide it by how many "speeds" they are: 60miles/hr divided by 3 if I continue my previous example.
It is my first answer, and I hope I could help you a bit!
Sorry for the awkward English, as it is not my mother tongue.
Step-by-step explanation:
Answer:borrowing the $960 for 1 week at an APR OF 350%, since doreen will owe less interest this way than with the fee of $70
Step-by-step explanation:
Well aint no explination i just guessed man
Answer:
576
Step-by-step explanation:
9514 1404 393
Answer:
90° CCW
Step-by-step explanation:
The transformation from B to B' is ...
B(-4, 1) ⇒ B'(-1, -4)
(x, y) ⇒ (-y, x) . . . . . matches the transformation for 90° CCW
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)
your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°
-> insert those values, with c substituted with b+3 to remove c
c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE
DE=CE+3=36+3=39
