3 years ago

Complete the table for the equation

Mathematics

1 answer:

Nataliya [291]3 years ago

5 0

Answer:

(2,5)

(3,-4)

(4,-7)

(5,-4)

(6,5)

You might be interested in

A teacher gave a test with 50 questions, each worth the a a teacher gave a test with 50 questions, each the same number of point

igomit [66]

Answer:

Marci answered 40 out of 50

Marci answered 2 more questions correctly.

Step-by-step explanation:

Donovan got 38 out of 50

Marci got 80% which means 40 out of 50

40-38 = 2

6 0

2 years ago

What is the volume of the right triangular prism shown?<br><br> for brainlist

emmainna [20.7K]

Answer: C

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Zoe, Latoya, Christina, and Rhoda each used a different method to verify that Negative 2 (3 x minus 12) = negative 6 x + 24.

mel-nik [20]

Answer:

Rhoda

Step-by-step explanation:

sub same values of x into both expressions. The expressions are equivalent if the values of the expressions are equal

5 0

3 years ago

Solve for

faust18 [17]

Given equation : n(17+x)=34x−r.

We need to solve it for x.

Distributing n over (17+x) on left side, we get

17n + nx = 34x - r.

Adding r on both sides, we get

17n+r + nx = 34x - r+r.

17n + r + nx = 34x.

Subtracting nx from both sides, we get

17n + r + nx-nx = 34x-nx

17n + r = 34x -nx.

Factoring out gcf x on right side, we get

17x + r = x(34-n).

Dividing both sides by (34-n), we get

$\frac{(17x + r)}{(34-n)} = \frac{x(34-n)}{(34-n)}$

$\frac{(17x + r)}{(34-n)} = x$

<h3>Therefore, final answer is $x=\frac{(17x + r)}{(34-n)}.$ </h3>

7 0

3 years ago

Read 2 more answers

I need help with this so could you give me the answers with an explanation if you can.

Katarina [22]

Answer:

$2.44745763 \times {10}^{6}$

Step-by-step explanation:

$R = \frac{ {x}^{2} }{y} \\ \\ = \frac{ {(3.8 \times {10}^{5}) }^{2} }{5.9 \times {10}^{4} } \\ \\ = \frac{14.44 \times {10}^{10} }{5.9 \times {10}^{4} } \\ \\ = 2.44745763 \times {10}^{10 - 4} \\ = 2.44745763 \times {10}^{6}$

4 0

3 years ago