Midpoint of (-2,-1) (-6,12)

Mathematics

1 answer:

Leni [432]2 years ago

6 0

Answer:

(-4, 5.5)

Step-by-step explanation:

1. put your Xs and Ys over 2

2. add them together

3. Divide

4. Simplify

5. Turn fraction into decimal

$m(x.y) \\ m = \frac{x1 + x2}{2} . \: \frac{y1 + y2}{2} \\ m = \: \frac{ - 2 + - 6}{2} . \frac{ - 1 + 12}{2} \\ m = ( - \frac{8}{2} . \frac{11}{2} ) \\ m = ( - 4 \: . \: 5 \frac{1}{2} ) \\ \\ \\ mid = ( - 4 \: \: . \: 5.5)$

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Pls answer 18 20 and 22 show your work

Svetlanka [38]

Answer:

18- 300

20- 1,500

22- 300

Step-by-step explanation:

You can easily find the answer like this:

18. Multiply 60 and 100 together. The hundred is from 100%. After that, divide it by 20 because of the percent. After doing this, you should get 300.

20. 360*100=36,000 36,000/24= 1,500

22. 9*100=900 900/3=300

I hope this is what you were looking for. If you need more out of this, ask me to answer it again. :)

5 0

3 years ago

(60 points)

natka813 [3]

Answer:

Step-by-step explanation:

$2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56$

$5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}$

$6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}$