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2 years ago

Midpoint of (-2,-1) (-6,12)

Mathematics

1 answer:

Leni [432]2 years ago

6 0

Answer:

(-4, 5.5)

Step-by-step explanation:

1. put your Xs and Ys over 2

2. add them together

3. Divide

4. Simplify

5. Turn fraction into decimal

$m(x.y) \\ m = \frac{x1 + x2}{2} . \: \frac{y1 + y2}{2} \\ m = \: \frac{ - 2 + - 6}{2} . \frac{ - 1 + 12}{2} \\ m = ( - \frac{8}{2} . \frac{11}{2} ) \\ m = ( - 4 \: . \: 5 \frac{1}{2} ) \\ \\ \\ mid = ( - 4 \: \: . \: 5.5)$

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3 years ago

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3 years ago

A survey of 100 families showed that 35 had a dog: 28 had a cat: 10 had a dog and a cat: 42 had neither a cat nor a dog nor a pa

nikdorinn [45]

<h2>Answer:</h2>

Option: C is the correct answer.

C. 5

<h2>Step-by-step explanation:</h2>

We will solve the following problem with the help of the Venn diagram.

Based on the Venn diagram we are asked to find the value of v i.e. those who have parakeet only.

From the information that:

35 had a dog we have:

x+y+10=35

i.e.

x+y=25

Also, based on the information :

28 had a cat we have:

u+z+10=28

i.e.

u+z=18

Also, 42 had neither a cat nor a dog nor a parakeet.

This means it cover the outer region of the three circles.

Total 100 families were surveyed it means that:

42+x+y+10+u+z+v=100

i.e. 42+25+10+18+v=100

i.e. 95+v=100

i.e. v=100-95

i.e. v=5

Hence, the number of families who have only parakeet are: 5

3 0

3 years ago