Solve the following inequalitys:

1 answer:

8 0

1) a > -5
2) b < 4
3) c > 4
4) d < 12
5) e < 8
6) h > 10

Leave all symbols as they were in the original inequality. I could not get the lines under the < or > for #2,3 and 5

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How do you solve this equation: -2m+3=|15+m|

Elden [556K]

Any number inside the modulus sign becomes positive. This means $|15+m|=|-(15+m)|=|-15-m|$ and so we have,

$-2m+3=|15+m| \Rightarrow \left \Big\{ {{-2m+3=15+m} \atop{-2m+3=-15-m}} \right$

Solving these gives us

$-2m+3=15+m \Rightarrow m=-4$

$-2m+3=-15-m \Rightarrow = m=18$

However if we check the second solution in the original equation we obtain $-2(18)+3=|15+18| \Rightarrow -33=33$ . This is false and so $m=18$ can't be a solution.

Therefore the only solution is $m=-4$ .

(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)

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Sin θ = 12/37. Find tan θ.

ivann1987 [24]

Answer:

Step-by-step explanation:

Use SOHCAHTOA.