Answer:
1 Rearrange the equation so "y" is on the left and everything else on the right.
2 Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
3 Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).
Step-by-step explanation:
X = number of dimes
x + 2 = number of nickels
3(x + 2) = number of pennies
10x + 5(x + 2) + 3(x + 2) = 52
10x + 5x + 10 + 3x + 6 = 52
18x = 36
x = 2
x = 2 (number of dimes)
x + 2 = 4 (number of nickels)
3(x + 2) = 12 (number of pennies)
Check:
2(10) = 20 cents in dimes
4(5) = 20 cents in nickels
12(1) = 12 cents in pennies
Total = 52 cents
The distance between the points is ≈6.4
Answer:
Step-by-step explanation:
We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.
Therefore we have the following raffle tickets:
123
132
213
231
312
321
000
000
From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.
Probability of 123 to be picked=
1/8 => 0.125
Probability of 000 to be picked=
2/8 => 0.25
Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked
Answer:
(-138) is the answer.
Step-by-step explanation:
Perfect square numbers between 15 and 25 inclusive are 16 and 25.
Sum of perfect square numbers 16 and 25 = 16 + 25 = 41
Sum of the remaining numbers between 15 and 25 inclusive means sum of the numbers from 17 to 24 plus 15.
Since sum of an arithmetic progression is defined by the expression
![S_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where n = number of terms
a = first term of the sequence
d = common difference
![S_{8}=\frac{8}{2} [2\times 17+(8-1)\times 1]](https://tex.z-dn.net/?f=S_%7B8%7D%3D%5Cfrac%7B8%7D%7B2%7D%20%5B2%5Ctimes%2017%2B%288-1%29%5Ctimes%201%5D)
= 4(34 + 7)
= 164
Sum of 15 + 
= 15 + 164 = 179
Now the difference between 41 and sum of perfect squares between 15 and 25 inclusive = 
= -138
Therefore, answer is (-138).
