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faust18 [17]
3 years ago
11

I aould appreciate if someone helped​

Mathematics
1 answer:
Anni [7]3 years ago
5 0
4/5 = 0.80
1/5 + 3/5 = 3/5 + 1/5
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Add all her phone bills = 115+43+67+95 =320, divide by how many numbers there are, so 4, 320 divided by 4 = 80
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What are the advantages and disadvantages to representing a function as an equation instead of a graph
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Read 2 more answers
What can you triple and then subtract by 7 to get -1
iVinArrow [24]

Answer:

2

Step-by-step explanation:

<em>let </em><em>the </em><em>number </em><em>be </em><em>x</em>

<em>The</em><em>n</em><em> </em><em>you </em><em>triple </em><em>the </em><em>x </em><em>and </em><em>minus </em><em>7 </em><em> </em><em>from </em><em>it </em><em>and </em><em>you </em><em>equate </em><em>it </em><em>to </em><em>-</em><em>1</em>

7 0
3 years ago
A popular soft drink is sold in 2-liter (2000 milliliter) bottles. Because of variation in the filling process, bottles have a m
andrezito [222]

Answer:

a) 0.27% probability that the mean is less than 1995 milliliters.

b) 2002.3 milliliters or more will occur only 10% of the time for the sample of 100 bottles.

Step-by-step explanation:

To solve this problem, it is important to understand the normal probability distribution and the central limit theorem

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2000, \sigma = 18

A) If the manufacturer samples 100 bottles, what is the probability that the mean is less than 1995 milliliters?

So n = 100, s = \frac{18}{\sqrt{100}} = 1.8

This probability is the pvalue of Z when X = 1995. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1995 - 2000}{1.8}

Z = -2.78

Z = -2.78 has a pvalue of 0.0027

So 0.27% probability that the mean is less than 1995 milliliters.

B) What mean overfill or more will occur only 10% of the time for the sample of 100 bottles?

This is the value of X when Z has a pvalue of 1-0.1 = 0.9.

So it is X when Z = 1.28

Z = \frac{X - \mu}{s}

1.28 = \frac{X - 2000}{1.8}

X - 2000 = 1.8*1.28

X = 2002.3

2002.3 milliliters or more will occur only 10% of the time for the sample of 100 bottles.

3 0
3 years ago
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