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anyanavicka [17]
3 years ago
7

The accompanying data on x = current density (mA/cm2) and y = rate of deposition (µm/min) appeared in an article. Do you agree w

ith the claim by the article's author that "a linear relationship was obtained from the tin-lead rate of deposition as a function of current density"? x 20 40 60 80 y 0.14 1.25 1.71 2.07 Find the value of r2. (Round your answer to three decimal places.) r2 =
Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

92.616%

Step-by-step explanation:

Given is the data of x and y where

x = current density (mA/cm2) and

y = rate of deposition (µm/min)

to find out whether there is linear relationship between x and y

x y

 

20 0.14

40 1.25

60 1.71

80 2.07

 

r 0.962364513

r^2 0.926145457

Since r is very near to 1, we find that there is a strong positive correlation and hence linearity can be assumed

r square the coefficient of determination is 0.9261 which is 92.616%

this is the measure which accounts for variation in x due to y and or variation in y due to x.

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\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }.


We can now simplify the bottom to read: 8u^{5} because when multiplying variables raised to an exponent, we add the exponents.  The expression now looks like:

\frac{2u^{3} v^{2} }{8u^{5} }


The 2/8 simplifies to 1/4:

\frac{u^{3} v^{2} }{4u^{5} }


Now, we have two u terms on the top and bottom.  When dividing variables raised to an exponent, we subtract the exponents.  However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent.  The final answer is:

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4 years ago
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Ludmilka [50]

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3 years ago
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3 years ago
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